Windows apps
Collapse the table of content
Expand the table of content
Information
The topic you requested is included in another documentation set. For convenience, it's displayed below. Choose Switch to see the topic in its original location.

String.GetEnumerator Method ()

 

Retrieves an object that can iterate through the individual characters in this string.

Namespace:   System
Assembly:  mscorlib (in mscorlib.dll)

Public Function GetEnumerator As CharEnumerator

Return Value

Type: System.CharEnumerator

An enumerator object.

System_CAPS_tipTip

Rather than calling the GetEnumerator method to retrieve a CharEnumerator object that you then use to enumerate a string, you should instead use your language's iteration construct ( in C#, in C++/CLR, and in Visual Basic). foreach in C#, for each in C++/CLR, and For Each in Visual Basic).

This method enables you to iterate the individual characters in a string. For example, the Visual Basic For Each and C# foreach statements invoke this method to return a CharEnumerator object that can provide read-only access to the characters in this string instance.

The following example iterates the characters in several strings and displays information about their individual characters. It uses the language iteration construct rather than a call to the GetEnumerator method.

Module Example
   Sub Main()
      EnumerateAndDisplay("Test Case")
      EnumerateAndDisplay("This is a sentence.")
      EnumerateAndDisplay("Has" & vbTab & "two" & vbTab & "tabs")
      EnumerateAndDisplay("Two" & vbLf & "new" & vbLf & "lines")
   End Sub 

   Sub EnumerateAndDisplay(phrase As String)
      Console.WriteLine("The characters in the string ""{0}"" are:", phrase)

      Dim charCount As Integer = 0
      Dim controlChars As Integer = 0
      Dim alphanumeric As Integer = 0
      Dim punctuation As Integer = 0

      For Each ch In phrase          
         Console.Write("'{0}' ", If(Not Char.IsControl(ch), ch, 
                                     "0x" + Convert.ToUInt16(ch).ToString("X4")))
         If Char.IsLetterOrDigit(ch) Then 
            alphanumeric += 1
         Else If Char.IsControl(ch) Then 
            controlChars += 1
         Else If Char.IsPunctuation(ch) Then 
            punctuation += 1             
         End If
         CharCount += 1
      Next

      Console.WriteLine()
      Console.WriteLine("   Total characters:        {0,3}", CharCount)
      Console.WriteLine("   Alphanumeric characters: {0,3}", alphanumeric)
      Console.WriteLine("   Punctuation characters:  {0,3}", punctuation)
      Console.WriteLine("   Control Characters:      {0,3}", controlChars)
      Console.WriteLine()
    End Sub 
End Module 
' This example displays the following output:
'    The characters in the string "Test Case" are:
'    'T' 'e' 's' 't' ' ' 'C' 'a' 's' 'e'
'       Total characters:          9
'       Alphanumeric characters:   8
'       Punctuation characters:    0
'       Control Characters:        0
'    
'    The characters in the string "This is a sentence." are:
'       'T' 'h' 'i' 's' ' ' 'i' 's' ' ' 'a' ' ' 's' 'e' 'n' 't' 'e' 'n' 'c' 'e' '.'
'          Total characters:         19
'          Alphanumeric characters:  15
'          Punctuation characters:    1
'          Control Characters:        0
'       
'       The characters in the string "Has       two     tabs" are:
'       'H' 'a' 's' '0x0009' 't' 'w' 'o' '0x0009' 't' 'a' 'b' 's'
'          Total characters:         12
'          Alphanumeric characters:  10
'          Punctuation characters:    0
'          Control Characters:        2
'       
'       The characters in the string "Two
'       new
'       lines" are:
'       'T' 'w' 'o' '0x000A' 'n' 'e' 'w' '0x000A' 'l' 'i' 'n' 'e' 's'
'          Total characters:         13
'          Alphanumeric characters:  11
'          Punctuation characters:    0
'          Control Characters:        2

.NET Framework
Available since 1.1
Return to top
Show:
© 2016 Microsoft