ReadElementContentAsDateTime Method
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XmlReader.ReadElementContentAsDateTime Method

[ This article is for Windows Phone 8 developers. If you’re developing for Windows 10, see the latest documentation. ]

Reads the current element and returns the contents as a DateTime object.

Namespace:  System.Xml
Assembly:  System.Xml (in System.Xml.dll)

public virtual DateTime ReadElementContentAsDateTime()

Return Value

Type: System.DateTime
The element content as a DateTime object.

ExceptionCondition
InvalidOperationException

The XmlReader is not positioned on an element.

XmlException

The current element contains child elements.

-or-

The element content cannot be converted to a DateTime object.

ArgumentNullException

The method is called with null arguments.

This method reads the start tag, the contents of the element, and moves the reader past the end element tag. It expands entities and ignores processing instructions and comments. The element can only contain simple content. That is, it cannot have child elements.



StringBuilder output = new StringBuilder();

String xmlString =
    @"<root>
    <stringValue>
    <!--comment-->
    <?some pi?>
        text value of the element.
    </stringValue>
    <longValue>270000000000001</longValue>
    <number>0</number>
    <double>2E10</double>
    <date>2003-01-08T15:00:00-00:00</date>
</root>";

using (XmlReader reader = XmlReader.Create(new StringReader(xmlString)))
{
    reader.ReadToFollowing("date");
    DateTime date = reader.ReadElementContentAsDateTime();

    // If the current culture is "en-US",
    // this writes "Wednesday, January 8, 2003".
    output.AppendLine(date.ToLongDateString());
}

OutputTextBlock.Text = output.ToString();


Windows Phone OS

Supported in: 8.1, 8.0, 7.1, 7.0

Windows Phone

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