SALES: 1-800-867-1380
Collapse the table of content
Expand the table of content
Expand Minimize
The topic you requested is included in another documentation set. For convenience, it's displayed below. Choose Switch to see the topic in its original location.

Enumerable.Max<TSource> Method (IEnumerable<TSource>, Func<TSource, Nullable<Double>>)


Invokes a transform function on each element of a sequence and returns the maximum nullable Double value.

Namespace:   System.Linq
Assembly:  System.Core (in System.Core.dll)

public static Nullable<double> Max<TSource>(
	this IEnumerable<TSource> source,
	Func<TSource, Nullable<double>> selector


Type: System.Collections.Generic.IEnumerable<TSource>

A sequence of values to determine the maximum value of.

Type: System.Func<TSource, Nullable<Double>>

A transform function to apply to each element.

Return Value

Type: System.Nullable<Double>

The value of type Nullable<Double> in C# or Nullable(Of Double) in Visual Basic that corresponds to the maximum value in the sequence.

Type Parameters


The type of the elements of source.

Exception Condition

source or selector is null.

The Max<TSource>(IEnumerable<TSource>, Func<TSource, Nullable<Double>>) method uses the Double implementation of IComparable<T> to compare values.

You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable<Double> in C# or Nullable(Of Double) in Visual Basic.

In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

The following code example demonstrates how to use Max<TSource>(IEnumerable<TSource>, Func<TSource, Int32>) to determine the maximum value in a sequence of projected values.


This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. To extend the example to this topic, change the body of the selector function.

class Pet
    public string Name { get; set; }
    public int Age { get; set; }

public static void MaxEx4()
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int max = pets.Max(pet => pet.Age + pet.Name.Length);

        "The maximum pet age plus name length is {0}.",

 This code produces the following output:

 The maximum pet age plus name length is 14.

Universal Windows Platform
Available since 4.5
.NET Framework
Available since 3.5
Portable Class Library
Supported in: portable .NET platforms
Available since 2.0
Windows Phone Silverlight
Available since 7.0
Windows Phone
Available since 8.1
Return to top
Was this page helpful?
(1500 characters remaining)
Thank you for your feedback
© 2015 Microsoft