이 문서는 기계 번역을 이용하여 번역되었습니다. 문서를 영문으로 보려면 영문 확인란을 선택하세요. 마우스 포인터를 텍스트 위로 이동시켜 팝업 창에서 영문 텍스트를 표시할 수도 있습니다.
번역
영문

String.GetEnumerator 메서드 ()

 

게시 날짜: 2016년 11월

이 문자열의 개별 문자에서 반복될 수 있는 개체를 검색합니다.

네임스페이스:   System
어셈블리:  mscorlib(mscorlib.dll에 있음)

public CharEnumerator GetEnumerator()

반환 값

Type: System.CharEnumerator

열거자 개체입니다.

System_CAPS_tip

Rather than calling the M:System.String.GetEnumerator method to retrieve a T:System.CharEnumerator object that you then use to enumerate a string, you should instead use your language's iteration construct ( in C#, in C++/CLR, and in Visual Basic). foreach in C#, for each in C++/CLR, and For Each in Visual Basic).

This method enables you to iterate the individual characters in a string. For example, the Visual Basic For Each and C# foreach statements invoke this method to return a T:System.CharEnumerator object that can provide read-only access to the characters in this string instance.

The following example iterates the characters in several strings and displays information about their individual characters. It uses the language iteration construct rather than a call to the M:System.String.GetEnumerator method.

using System;

class Example
{
   public static void Main() 
   {
      EnumerateAndDisplay("Test Case");
      EnumerateAndDisplay("This is a sentence.");
      EnumerateAndDisplay("Has\ttwo\ttabs" );
      EnumerateAndDisplay("Two\nnew\nlines");
   }

   static void EnumerateAndDisplay(String phrase)
   {
      Console.WriteLine("The characters in the string \"{0}\" are:",
                        phrase);

      int CharCount = 0;
      int controlChars = 0;
      int alphanumeric = 0;
      int punctuation = 0;

      foreach (var ch in phrase) {
         Console.Write("'{0}' ", ! Char.IsControl(ch) ? ch.ToString() : 
                                     "0x" + Convert.ToUInt16(ch).ToString("X4"));
         if (Char.IsLetterOrDigit(ch)) 
            alphanumeric++;
         else if (Char.IsControl(ch)) 
            controlChars++;
         else if (Char.IsPunctuation(ch)) 
            punctuation++;             
         CharCount++;
      }

      Console.WriteLine("\n   Total characters:        {0,3}", CharCount);
      Console.WriteLine("   Alphanumeric characters: {0,3}", alphanumeric);
      Console.WriteLine("   Punctuation characters:  {0,3}", punctuation);
      Console.WriteLine("   Control Characters:      {0,3}\n", controlChars);
   }
}
// The example displays the following output:
//    The characters in the string "Test Case" are:
//    'T' 'e' 's' 't' ' ' 'C' 'a' 's' 'e'
//       Total characters:          9
//       Alphanumeric characters:   8
//       Punctuation characters:    0
//       Control Characters:        0
//    
//    The characters in the string "This is a sentence." are:
//    'T' 'h' 'i' 's' ' ' 'i' 's' ' ' 'a' ' ' 's' 'e' 'n' 't' 'e' 'n' 'c' 'e' '.'
//       Total characters:         19
//       Alphanumeric characters:  15
//       Punctuation characters:    1
//       Control Characters:        0
//    
//    The characters in the string "Has       two     tabs" are:
//    'H' 'a' 's' '0x0009' 't' 'w' 'o' '0x0009' 't' 'a' 'b' 's'
//       Total characters:         12
//       Alphanumeric characters:  10
//       Punctuation characters:    0
//       Control Characters:        2
//    
//    The characters in the string "Two
//    new
//    lines" are:
//    'T' 'w' 'o' '0x000A' 'n' 'e' 'w' '0x000A' 'l' 'i' 'n' 'e' 's'
//       Total characters:         13
//       Alphanumeric characters:  11
//       Punctuation characters:    0
//       Control Characters:        2

.NET Framework
1.1 이후 사용 가능
맨 위로 이동
표시: