isgraph
ロケールの要素が英数字または区切り文字であるかどうかをテストします。
template<Class CharType>
bool isgraph(
CharType _Ch,
const locale& _Loc
)
パラメーター
_Ch
テストする要素。_Loc
テストされる要素を含むロケール。
戻り値
テストされる要素は英数字または区切り文字の場合true ; ある false。
解説
このテンプレート関数は use_facet<ctype<CharType>> を返します (_Loc)。です。 (ctype<CharTypeの >::graph、_Ch)。
使用例
// locale_is_graph.cpp
// compile with: /EHsc
#include <locale>
#include <iostream>
using namespace std;
int main( )
{
locale loc ( "German_Germany" );
bool result1 = isgraph ( 'L', loc );
bool result2 = isgraph ( '\t', loc );
bool result3 = isgraph ( '.', loc );
if ( result1 )
cout << "The character 'L' in the locale is\n "
<< "an alphanumeric or punctuation character." << endl;
else
cout << "The character 'L' in the locale is\n "
<< " not an alphanumeric or punctuation character." << endl;
if ( result2 )
cout << "The character 'backslash-t' in the locale is\n "
<< "an alphanumeric or punctuation character." << endl;
else
cout << "The character 'backslash-t' in the locale is\n "
<< "not an alphanumeric or punctuation character." << endl;
if ( result3 )
cout << "The character '.' in the locale is\n "
<< "an alphanumeric or punctuation character." << endl;
else
cout << "The character '.' in the locale is\n "
<< " not an alphanumeric or punctuation character." << endl;
}
出力
The character 'L' in the locale is
an alphanumeric or punctuation character.
The character 'backslash-t' in the locale is
not an alphanumeric or punctuation character.
The character '.' in the locale is
an alphanumeric or punctuation character.
必要条件
ヘッダー: <locale>
名前空間: std