InOutArgument<T>.FromExpression Metodo

  • Riferimento

Definizione

Spazio dei nomi:
System.Activities
Assembly:
System.Activities.dll

Inizializza e restituisce un nuovo InOutArgument<T> costruito utilizzando il Activity<TResult> specificato.

public:
 static System::Activities::InOutArgument<T> ^ FromExpression(System::Activities::Activity<System::Activities::Location<T> ^> ^ expression);
public static System.Activities.InOutArgument<T> FromExpression (System.Activities.Activity<System.Activities.Location<T>> expression);
static member FromExpression : System.Activities.Activity<System.Activities.Location<'T>> -> System.Activities.InOutArgument<'T>
Public Shared Function FromExpression (expression As Activity(Of Location(Of T))) As InOutArgument(Of T)

Parametri

expression
Activity<Location<T>>

Valore dell'argomento.

Restituisce

InOutArgument<T>

Nuovo argomento.

Si applica a