isspace

Comprueba si un elemento en una configuración regional es un carácter de espacio en blanco.

template<Class CharType>
   bool isspace(
      CharType _Ch, 
      const locale& _Loc
   )

Parámetros

• _Ch
  El elemento que se va a probar.

• _Loc
  Configuración regional que contiene el elemento que se va a probar.

Valor devuelto

TRUE si el elemento probado es un carácter de espacio en blanco; Falso si no es.

Comentarios

la función de la plantilla devuelve use_facet<C<CharType> > (_Loc).es(C<CharType>::espacio, _Ch).

Ejemplo

// locale_isspace.cpp
// compile with: /EHsc
#include <locale>
#include <iostream>

using namespace std;

int main( )   
{
   locale loc ( "German_Germany" );
   bool result1 = isspace ( 'L', loc );
   bool result2 = isspace ( '\n', loc );
   bool result3 = isspace ( ' ', loc );

   if ( result1 )
      cout << "The character 'L' in the locale is "
           << "a whitespace character." << endl;
   else
      cout << "The character 'L' in the locale is "
           << " not a whitespace character." << endl;

   if ( result2 )
      cout << "The character 'backslash-n' in the locale is "
           << "a whitespace character." << endl;
   else
      cout << "The character 'backslash-n' in the locale is "
           << " not a whitespace character." << endl;

   if ( result3 )
      cout << "The character ' ' in the locale is "
           << "a whitespace character." << endl;
   else
      cout << "The character ' ' in the locale is "
           << " not a whitespace character." << endl;
}

Output

The character 'L' in the locale is  not a whitespace character.
The character 'backslash-n' in the locale is a whitespace character.
The character ' ' in the locale is a whitespace character.

Requisitos

encabezado: <configuración regional>

espacio de nombres: std