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EnumerableMin Method

Invokes a transform function on each element of a sequence and returns the minimum Int64 value.

Namespace:   System.Linq
Assembly:  System.Core (in System.Core.dll)

public static long Min<TSource>(
	this IEnumerable<TSource> source,
	Func<TSource, long> selector
generic<typename TSource>
static long long Min(
	IEnumerable<TSource>^ source,
	Func<TSource, long long>^ selector
static member Min<'TSource> : 
        source:IEnumerable<'TSource> *
        selector:Func<'TSource, int64> -> int64
Public Shared Function Min(Of TSource) (
	source As IEnumerable(Of TSource),
	selector As Func(Of TSource, Long)
) As Long



A sequence of values to determine the minimum value of.


A transform function to apply to each element.

Return Value


The minimum value in the sequence.

Type Parameters


The type of the elements of source.

Exception Condition

source or selector is null.


source contains no elements.


The Min method uses the Int64 implementation of IComparable to compare values.

You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Int64.

In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.


The following code example demonstrates how to use Min to determine the minimum value in a sequence of projected values.


This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. To extend the example to this topic, change the body of the selector function.

class Pet
    public string Name { get; set; }
    public int Age { get; set; }

public static void MinEx4()
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int min = pets.Min(pet => pet.Age);

    Console.WriteLine("The youngest animal is age {0}.", min);

 This code produces the following output:

 The youngest animal is age 1.  
Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MinEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8}, _
                         New Pet With {.Name = "Boots", .Age = 4}, _
                         New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Find the youngest pet by passing a 
    ' lambda expression to the Min() method.
    Dim min As Integer = pets.Min(Function(pet) pet.Age)

    ' Display the result.
    MsgBox("The youngest pet is age " & min)
End Sub

' This code produces the following output:
' The youngest pet is age 1
Version Information
Universal Windows Platform
Available since 4.5
.NET Framework
Available since 3.5
Portable Class Library
Supported in: portable .NET platforms
Available since 2.0
Windows Phone Silverlight
Available since 7.0
Windows Phone
Available since 8.1
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