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.NET Framework Class Library
EnumerableLastTSource Method (IEnumerableTSource)

Returns the last element of a sequence.

Namespace:   System.Linq
Assemblies:   System.Linq (in System.Linq.dll)
  System.Core (in System.Core.dll)
Syntax
<[%$TOPIC/bb358775_en-us_VS_110_1_0_0_0_0%]> _
Public Shared Function Last(Of TSource) ( _
	source As [%$TOPIC/bb358775_en-us_VS_110_1_0_0_0_1%](Of TSource) _
) As TSource
public static TSource Last<TSource>(
	this [%$TOPIC/bb358775_en-us_VS_110_1_0_1_0_0%]<TSource> source
)
[[%$TOPIC/bb358775_en-us_VS_110_1_0_2_0_0%]]
public:
generic<typename TSource>
static TSource Last(
	[%$TOPIC/bb358775_en-us_VS_110_1_0_2_0_1%]<TSource>^ source
)
static member Last : 
        source:[%$TOPIC/bb358775_en-us_VS_110_1_0_3_0_0%]<'TSource> -> 'TSource 
JScript does not support generic types or methods.

Type Parameters

TSource

The type of the elements of source.

Parameters

source
Type: System.Collections.GenericIEnumerableTSource

An IEnumerableT to return the last element of.

Return Value

Type: TSource
The value at the last position in the source sequence.

Usage Note

In Visual Basic and C#, you can call this method as an instance method on any object of type IEnumerableTSource. When you use instance method syntax to call this method, omit the first parameter. For more information, see Extension Methods (Visual Basic) or Extension Methods (C# Programming Guide).
Exceptions
ExceptionCondition
ArgumentNullException

source is .

InvalidOperationException

The source sequence is empty.

Remarks

The LastTSource(IEnumerableTSource) method throws an exception if source contains no elements. To instead return a default value when the source sequence is empty, use the LastOrDefault method.

Examples

The following code example demonstrates how to use LastTSource(IEnumerableTSource) to return the last element of an array.

        ' Create an array of integers. 
        Dim numbers() As Integer = _
            {9, 34, 65, 92, 87, 435, 3, 54, 83, 23, 87, 67, 12, 19}

        ' Get the last item in the array. 
        Dim last As Integer = numbers.Last()

        ' Display the result.
        MsgBox(last)

        ' This code produces the following output: 
        ' 
        ' 19
int[] numbers = { 9, 34, 65, 92, 87, 435, 3, 54, 
                                83, 23, 87, 67, 12, 19 };

            int last = numbers.Last();

            Console.WriteLine(last);

            /*
             This code produces the following output:

             19
            */
Version Information

.NET Framework

Supported in: 4.6, 4.5, 4, 3.5

.NET Framework Client Profile

Supported in: 4, 3.5 SP1

XNA Framework

Supported in: 3.0

Portable Class Library

Supported in: Portable Class Library

Supported in: Windows Phone 8.1

Supported in: Windows Phone Silverlight 8.1

Supported in: Windows Phone Silverlight 8