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EnumerableElementAt Method

Returns the element at a specified index in a sequence.

Namespace:   System.Linq
Assembly:  System.Core (in System.Core.dll)

public static TSource ElementAt<TSource>(
	this IEnumerable<TSource> source,
	int index
generic<typename TSource>
static TSource ElementAt(
	IEnumerable<TSource>^ source,
	int index
static member ElementAt<'TSource> : 
        source:IEnumerable<'TSource> *
        index:int -> 'TSource
Public Shared Function ElementAt(Of TSource) (
	source As IEnumerable(Of TSource),
	index As Integer
) As TSource



An IEnumerable to return an element from.


The zero-based index of the element to retrieve.

Return Value

Type: TSource

The element at the specified position in the source sequence.

Type Parameters


The type of the elements of source.

Exception Condition

source is null.


index is less than 0 or greater than or equal to the number of elements in source.


If the type of source implements IList, that implementation is used to obtain the element at the specified index. Otherwise, this method obtains the specified element.

This method throws an exception if index is out of range. To instead return a default value when the specified index is out of range, use the ElementAtOrDefault method.


The following code example demonstrates how to use ElementAt to return an element at a specific position.

string[] names =
    { "Hartono, Tommy", "Adams, Terry", "Andersen, Henriette Thaulow", 

        "Hedlund, Magnus", "Ito, Shu" };
Random random = new Random(DateTime.Now.Millisecond);

string name = names.ElementAt(random.Next(0, names.Length));

Console.WriteLine("The name chosen at random is '{0}'.", name);

 This code produces the following sample output:

 The name chosen at random is 'Ito, Shu'.
' Create an array of strings.
Dim names() As String = _
    {"Hartono, Tommy", "Adams, Terry", "Andersen, Henriette Thaulow", "Hedlund, Magnus", "Ito, Shu"}

Dim random As Random = New Random(DateTime.Now.Millisecond)

' Get a string at a random index within the array.
Dim name As String = names.ElementAt(random.Next(0, names.Length))

' Display the output.
MsgBox("The name chosen at random is " & name)

' This code produces the following output:
' The name chosen at random is Ito, Shu
Version Information
Universal Windows Platform
Available since 8
.NET Framework
Available since 3.5
Portable Class Library
Supported in: portable .NET platforms
Available since 2.0
Windows Phone Silverlight
Available since 7.0
Windows Phone
Available since 8.1
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