Compiler Error C2064
term does not evaluate to a function taking 'number' arguments
A call is made to a function through an expression. The expression does not evaluate to a function pointer.
The following sample generates C2064:
// C2064.cpp
int i, j;
char* p;
void func() {
j = i(); // C2064, i is not a function
p(); // C2064, p doesn't point to a function
}
The following sample generates C2064:
// C2064b.cpp
struct C {
void func1(){}
void func2(){}
};
typedef void (C::*pFunc)();
int main() {
C c;
pFunc funcArray[2] = {&C::func1, &C::func2};
(funcArray[0])(); // C2064
}
Possible resolution:
// C2064c.cpp
struct C {
void func1(){}
void func2(){}
};
typedef void (C::*pFunc)();
int main() {
C c;
pFunc funcArray[2] = {&C::func1, &C::func2};
(c.* funcArray[0])();
}
The following sample generates C2064:
// C2064d.cpp
struct C {
typedef void (C::*pFunc)();
pFunc funcArray[2];
void func1(){}
void func2(){}
C() {
funcArray[0] = C::func1;
funcArray[1] = C::func2;
}
void func3() {
(funcArray[0])(); // C2064
}
};
Possible resolution:
// C2064e.cpp
// compile with: /c
struct C {
typedef void (C::*pFunc)();
pFunc funcArray[2];
void func1(){}
void func2(){}
C() {
funcArray[0] = &C::func1;
funcArray[1] = &C::func2;
}
void func3() {
(this->* funcArray[0])();
}
};