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DataGrid Class

Displays ADO.NET data in a scrollable grid. The DataGridView control replaces and adds functionality to the DataGrid control; however, the DataGrid control is retained for both backward compatibility and future use, if you choose.

Namespace: System.Windows.Forms
Assembly: System.Windows.Forms (in

<ComVisibleAttribute(True)> _
<ClassInterfaceAttribute(ClassInterfaceType.AutoDispatch)> _
Public Class DataGrid
	Inherits Control
	Implements ISupportInitialize, IDataGridEditingService
Dim instance As DataGrid

/** @attribute ComVisibleAttribute(true) */ 
/** @attribute ClassInterfaceAttribute(ClassInterfaceType.AutoDispatch) */ 
public class DataGrid extends Control implements ISupportInitialize, IDataGridEditingService
public class DataGrid extends Control implements ISupportInitialize, IDataGridEditingService
Not applicable.

The System.Windows.Forms.DataGrid displays Web-like links to child tables. You can click on a link to navigate to the child table. When a child table is displayed, a back button appears in the caption that can be clicked to navigate back to the parent table. The data from the parent rows is displayed below the caption and above the column headers. You can hide the parent row information by clicking the button to the right of the back button.

To display a table in the System.Windows.Forms.DataGrid at run time, use the SetDataBinding method to set the DataSource and DataMember properties to a valid data source. The following data sources are valid:

For more information about the DataSet class, see Using DataSets in ADO.NET.

You can create a grid that enables users to edit data but prevents them from adding new rows by using a DataView as the data source and setting the AllowNew property to false.

Data sources are further managed by BindingManagerBase objects. For each table in a data source, a BindingManagerBase can be returned from the form's BindingContext. For example, you can determine the number of rows contained by a data source by returning the associated BindingManagerBase object's Count property.

To validate data, use the underlying objects that represent data and their events. For example, if the data comes from a DataTable in a DataSet, use the ColumnChanging and RowChanging events.


Because the number of columns can be customized (by adding or deleting members of the GridColumnStylesCollection) and the rows can be sorted by column, the RowNumber and ColumnNumber property values cannot be guaranteed to correspond to DataRow and DataColumn indexes in a DataTable. Therefore you should avoid using those properties in the Validating event to validate data.

To determine which cell is selected, use the CurrentCell property. Change the value of any cell by using the Item property, which can take either the row and column indexes of the cell, or a single DataGridCell. Monitor the CurrentCellChanged event to detect when the user selects another cell.

To determine which part of the control the user clicked, use the HitTest method in the MouseDown event. The HitTest method returns a DataGrid.HitTestInfo object, which contains the row and column of a clicked area.

To manage the appearance of the control at run time, several properties for setting the color and caption attributes are available, including the CaptionForeColor, CaptionBackColor, CaptionFont, and so on.

The appearance of the displayed grid (or grids) can be further modified by creating DataGridTableStyle objects and adding them to the GridTableStylesCollection, which is accessed through the TableStyles property. For example, if the DataSource is set to a DataSet containing three DataTable objects, you can add three DataGridTableStyle objects to the collection, one for each table. To synchronize each DataGridTableStyle object with a DataTable, set the MappingName of the DataGridTableStyle to the TableName of the DataTable. For more information about binding to an array of objects, see the DataGridTableStyle.MappingName property.

To create a customized view of a table, create an instance of a DataGridTextBoxColumn or DataGridBoolColumn class and add the object to the GridTableStylesCollection accessed through the TableStyles property. Both classes inherit from DataGridColumnStyle. For each column style, set the MappingName to the ColumnName of a column that you want to show in the grid. To hide a column, set its MappingName to something other than a valid ColumnName.

To format the text of a column, set the Format property of the DataGridTextBoxColumn to one of the values found in Date and Time Format Strings or Standard Numeric Format Strings.

To bind the DataGrid to a strongly typed array of objects, the object type must contain public properties. To create a DataGridTableStyle that displays the array, set the DataGridTableStyle.MappingName property to typename[] where typename is replaced by the name of the object type. Also note that the MappingName property is case-sensitive; the type name must be matched exactly. See the MappingName property for an example.

You can also bind the DataGrid to an ArrayList. A feature of the ArrayList is that it can contain objects of multiple types, but the DataGrid can only bind to such a list when all items in the list are of the same type as the first item. This means that all objects must either be of the same type, or they must inherit from the same class as the first item in the list. For example, if the first item in a list is a Control, the second item could be a TextBox (which inherits from Control). If, on the other hand, the first item is a TextBox, the second object cannot be a Control. Further, the ArrayList must have items in it when it is bound. An empty ArrayList will result in an empty grid. In addition, the objects in the ArrayList must contain public properties. When binding to an ArrayList, set the MappingName of the DataGridTableStyle to "ArrayList" (the type name).

For each DataGridTableStyle, you can set color and caption attributes that override the settings for the System.Windows.Forms.DataGrid control. However, if those properties are not set, the settings for the control are used by default. The following properties can be overridden by DataGridTableStyle properties:

To customize the appearance of individual columns, add DataGridColumnStyle objects to the GridColumnStylesCollection, which is accessed through the GridColumnStyles property of each DataGridTableStyle. To synchronize each DataGridColumnStyle with a DataColumn in the DataTable, set the MappingName to the ColumnName of a DataColumn. When constructing a DataGridColumnStyle, you can also set a formatting string that specifies how the column displays data. For example, you can specify that the column use a short-date format to display dates contained in the table.

Caution noteCaution:

Always create DataGridColumnStyle objects and add them to the GridColumnStylesCollection before adding DataGridTableStyle objects to the GridTableStylesCollection. When you add an empty DataGridTableStyle with a valid MappingName value to the collection, DataGridColumnStyle objects are automatically generated for you. Consequently, an exception will be thrown if you try to add new DataGridColumnStyle objects with duplicate MappingName values to the GridColumnStylesCollection.


The DataGridView control replaces and adds functionality to the DataGrid control; however, the DataGrid control is retained for both backward compatibility and future use, if you choose. For more information, see Differences Between the Windows Forms DataGridView and DataGrid Controls.

The following code example creates a Windows form, a DataSet containing two DataTable objects, and a DataRelation that relates the two tables. To display the data, a System.Windows.Forms.DataGrid control is then bound to the DataSet through the SetDataBinding method. A button on the form changes the appearance of the grid by creating two DataGridTableStyle objects and setting the MappingName of each object to a TableName of one of the DataTable objects. The example also contains code in the MouseUp event that uses the HitTest method to print the column, row, and part of the grid that has been clicked.

Option Explicit
Option Strict

Imports System
Imports System.ComponentModel
Imports System.Data
Imports System.Drawing
Imports System.Windows.Forms

Public Class Form1
   Inherits System.Windows.Forms.Form
   Private components As System.ComponentModel.Container
   Private button1 As Button
   Private button2 As Button
   Private myDataGrid As DataGrid
   Private myDataSet As DataSet
   Private TablesAlreadyAdded As Boolean    
   Public Sub New()
      ' Required for Windows Form Designer support.
      ' Call SetUp to bind the controls.
   End Sub 
  Private Sub InitializeComponent()
      ' Create the form and its controls.
      Me.components = New System.ComponentModel.Container()
      Me.button1 = New System.Windows.Forms.Button()
      Me.button2 = New System.Windows.Forms.Button()
      Me.myDataGrid = New DataGrid()
      Me.Text = "DataGrid Control Sample"
      Me.ClientSize = New System.Drawing.Size(450, 330)
      button1.Location = New Point(24, 16)
      button1.Size = New System.Drawing.Size(120, 24)
      button1.Text = "Change Appearance"
      AddHandler button1.Click, AddressOf button1_Click
      button2.Location = New Point(150, 16)
      button2.Size = New System.Drawing.Size(120, 24)
      button2.Text = "Get Binding Manager"
      AddHandler button2.Click, AddressOf button2_Click
      myDataGrid.Location = New Point(24, 50)
      myDataGrid.Size = New Size(300, 200)
      myDataGrid.CaptionText = "Microsoft DataGrid Control"
      AddHandler myDataGrid.MouseUp, AddressOf Grid_MouseUp
   End Sub 
   Public Shared Sub Main()
      Application.Run(New Form1())
   End Sub 
   Private Sub SetUp()
      ' Create a DataSet with two tables and one relation.
      ' Bind the DataGrid to the DataSet. The dataMember
      ' specifies that the Customers table should be displayed.
      myDataGrid.SetDataBinding(myDataSet, "Customers")
   End Sub 
    Private Sub button1_Click(ByVal sender As Object, ByVal e As System.EventArgs)
        If TablesAlreadyAdded = True Then Exit Sub
    End Sub
   Private Sub AddCustomDataTableStyle()
      Dim ts1 As New DataGridTableStyle()
      ts1.MappingName = "Customers"
      ' Set other properties.
      ts1.AlternatingBackColor = Color.LightGray
      ' Add a GridColumnStyle and set its MappingName 
      ' to the name of a DataColumn in the DataTable. 
      ' Set the HeaderText and Width properties. 
      Dim boolCol As New DataGridBoolColumn()
      boolCol.MappingName = "Current"
      boolCol.HeaderText = "IsCurrent Customer"
      boolCol.Width = 150
      ' Add a second column style.
      Dim TextCol As New DataGridTextBoxColumn()
      TextCol.MappingName = "custName"
      TextCol.HeaderText = "Customer Name"
      TextCol.Width = 250
      ' Create the second table style with columns.
      Dim ts2 As New DataGridTableStyle()
      ts2.MappingName = "Orders"
      ' Set other properties.
      ts2.AlternatingBackColor = Color.LightBlue
      ' Create new ColumnStyle objects
      Dim cOrderDate As New DataGridTextBoxColumn()
      cOrderDate.MappingName = "OrderDate"
      cOrderDate.HeaderText = "Order Date"
      cOrderDate.Width = 100

      ' Use a PropertyDescriptor to create a formatted
      ' column. First get the PropertyDescriptorCollection
      ' for the data source and data member. 
      Dim pcol As PropertyDescriptorCollection = _
      Me.BindingContext(myDataSet, "Customers.custToOrders"). _

      ' Create a formatted column using a PropertyDescriptor.
      ' The formatting character "c" specifies a currency format. */     
      Dim csOrderAmount As _
      New DataGridTextBoxColumn(pcol("OrderAmount"), "c", True)
      csOrderAmount.MappingName = "OrderAmount"
      csOrderAmount.HeaderText = "Total"
      csOrderAmount.Width = 100
      ' Add the DataGridTableStyle instances to 
      ' the GridTableStylesCollection. 

     ' Sets the TablesAlreadyAdded to true so this doesn't happen again.
      TablesAlreadyAdded = true
   End Sub 
    Private Sub button2_Click(ByVal sender As Object, ByVal e As System.EventArgs)
        Dim bmGrid As BindingManagerBase
        bmGrid = BindingContext(myDataSet, "Customers")
        MessageBox.Show(("Current BindingManager Position: " & bmGrid.Position))
    End Sub
   Private Sub Grid_MouseUp(sender As Object, e As MouseEventArgs)
      ' Create a HitTestInfo object using the HitTest method.
      ' Get the DataGrid by casting sender.
      Dim myGrid As DataGrid = CType(sender, DataGrid)
      Dim myHitInfo As DataGrid.HitTestInfo = myGrid.HitTest(e.X, e.Y)
   End Sub 
   ' Create a DataSet with two tables and populate it.
   Private Sub MakeDataSet()
      ' Create a DataSet.
      myDataSet = New DataSet("myDataSet")
      ' Create two DataTables.
      Dim tCust As New DataTable("Customers")
      Dim tOrders As New DataTable("Orders")
      ' Create two columns, and add them to the first table.
      Dim cCustID As New DataColumn("CustID", GetType(Integer))
      Dim cCustName As New DataColumn("CustName")
      Dim cCurrent As New DataColumn("Current", GetType(Boolean))
      ' Create three columns, and add them to the second table.
      Dim cID As New DataColumn("CustID", GetType(Integer))
      Dim cOrderDate As New DataColumn("orderDate", GetType(DateTime))
      Dim cOrderAmount As New DataColumn("OrderAmount", GetType(Decimal))
      ' Add the tables to the DataSet.
      ' Create a DataRelation, and add it to the DataSet.
      Dim dr As New DataRelation("custToOrders", cCustID, cID)
      ' Populates the tables. For each customer and order, 
      ' creates two DataRow variables. 
      Dim newRow1 As DataRow
      Dim newRow2 As DataRow
      ' Create three customers in the Customers Table.
      Dim i As Integer
      For i = 1 To 3
         newRow1 = tCust.NewRow()
         newRow1("custID") = i
         ' Add the row to the Customers table.
      Next i
      ' Give each customer a distinct name.
      tCust.Rows(0)("custName") = "Customer1"
      tCust.Rows(1)("custName") = "Customer2"
      tCust.Rows(2)("custName") = "Customer3"
      ' Give the Current column a value.
      tCust.Rows(0)("Current") = True
      tCust.Rows(1)("Current") = True
      tCust.Rows(2)("Current") = False
      ' For each customer, create five rows in the Orders table.
      For i = 1 To 3
         Dim j As Integer
         For j = 1 To 5
            newRow2 = tOrders.NewRow()
            newRow2("CustID") = i
            newRow2("orderDate") = New DateTime(2001, i, j * 2)
            newRow2("OrderAmount") = i * 10 + j * 0.1
            ' Add the row to the Orders table.
         Next j
      Next i
   End Sub 
End Class 

Any public static (Shared in Visual Basic) members of this type are thread safe. Any instance members are not guaranteed to be thread safe.

Windows 98, Windows Server 2000 SP4, Windows CE, Windows Millennium Edition, Windows Mobile for Pocket PC, Windows Mobile for Smartphone, Windows Server 2003, Windows XP Media Center Edition, Windows XP Professional x64 Edition, Windows XP SP2, Windows XP Starter Edition

The Microsoft .NET Framework 3.0 is supported on Windows Vista, Microsoft Windows XP SP2, and Windows Server 2003 SP1.

.NET Framework

Supported in: 3.0, 2.0, 1.1, 1.0

.NET Compact Framework

Supported in: 2.0, 1.0

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