SysAllocStringLen function
Allocates a new string, copies the specified number of characters from the passed string, and appends a null-terminating character.
Syntax
BSTR SysAllocStringLen(
_In_ const OLECHAR *strIn,
_In_ UINT ui
);
Parameters
- strIn [in]
-
The input string.
- ui [in]
-
The number of characters to copy. A null character is placed afterwards, allocating a total of ui plus one characters.
Return value
A copy of the string, or NULL if there is insufficient memory to complete the operation.
Remarks
The string can contain embedded null characters and does not need to end with a NULL. Free the returned string later with SysFreeString. If strIn is not NULL, then the memory allocated to strIn must be at least ui characters long.
Requirements
|
Header |
|
|---|---|
|
Library |
|
|
DLL |
|
See also