String.Join Method (String, array<String[], Int32, Int32)

Parameters

• separator
  Type: System.String
  The string to use as a separator.

• value
  Type: array<System.String[]
  An array that contains the elements to concatenate.

• startIndex
  Type: System.Int32
  The first element in value to use.

• count
  Type: System.Int32
  The number of elements in value to use.

Return Value

Type: System.String
A string that consists of the strings in value delimited by the separator string.
-or-
String.Empty if count is zero, value has no elements, or separator and all the elements of value are String.Empty.

' Sample for String.Join(String, String[], int int)
 _

Class Example

   Public Shared Sub Demo(ByVal outputBlock As System.Windows.Controls.TextBlock)
      Dim val As [String]() = {"apple", "orange", "grape", "pear"}
      Dim sep As [String] = ", "
      Dim result As [String]

      outputBlock.Text += String.Format("sep = '{0}'", sep) & vbCrLf
      outputBlock.Text += String.Format("val() = {{'{0}' '{1}' '{2}' '{3}'}}", val(0), val(1), val(2), val(3)) & vbCrLf
      result = [String].Join(sep, val, 1, 2)
      outputBlock.Text += String.Format("String.Join(sep, val, 1, 2) = '{0}'", result) & vbCrLf
   End Sub 'Main
End Class 'Sample
'
'This example produces the following results:
'sep = ', '
'val() = {'apple' 'orange' 'grape' 'pear'}
'String.Join(sep, val, 1, 2) = 'orange, grape'
'

// Sample for String.Join(String, String[], int int)
using System;

class Example
{
   public static void Demo(System.Windows.Controls.TextBlock outputBlock)
   {
      String[] val = { "apple", "orange", "grape", "pear" };
      String sep = ", ";
      String result;

      outputBlock.Text += String.Format("sep = '{0}'", sep) + "\n";
      outputBlock.Text += String.Format("val[] = {{'{0}' '{1}' '{2}' '{3}'}}", val[0], val[1], val[2], val[3]) + "\n";
      result = String.Join(sep, val, 1, 2);
      outputBlock.Text += String.Format("String.Join(sep, val, 1, 2) = '{0}'", result) + "\n";
   }
}
/*
This example produces the following results:
sep = ', '
val[] = {'apple' 'orange' 'grape' 'pear'}
String.Join(sep, val, 1, 2) = 'orange, grape'
*/