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Color.FromArgb Method

Creates a new Color structure by using the specified sRGB alpha channel and color channel values.

Namespace:  System.Windows.Media
Assembly:  PresentationCore (in PresentationCore.dll)

public static Color FromArgb(
	byte a,
	byte r,
	byte g,
	byte b
You cannot use methods in XAML.


Type: System.Byte

The alpha channel, A, of the new color.

Type: System.Byte

The red channel, R, of the new color.

Type: System.Byte

The green channel, G, of the new color.

Type: System.Byte

The blue channel, B, of the new color.

Return Value

Type: System.Windows.Media.Color
A Color structure with the specified values.

The FromArgb method allows you to specify the alpha channel; the FromRgb method uses a default value of 1 for the alpha channel.

The alpha channel of a color determines the amount of transparency of the color. An alpha value of 1 indicates that the color is completely opaque, and a value of 0 indicates that the color is completely transparent.

The sRGB channels (A, R, G, B) and the ScRGB channels (ScA, ScR, ScG, ScB) of the Color structure are synchronized properties. For example, when R, the sRGB red channel, is modified, the ScRGB red channel, ScR, is transformed to the equivalent value.

The following example shows how to use the FromArgb method to create a Color structure.

private Color FromArgbExample()
    // Create a blue color using the FromArgb static method.
    Color myArgbColor = new Color();
    myArgbColor = Color.FromArgb(255, 0, 255, 0);
    return myArgbColor;

Windows 7, Windows Vista, Windows XP SP2, Windows Server 2008 R2, Windows Server 2008, Windows Server 2003

The .NET Framework and .NET Compact Framework do not support all versions of every platform. For a list of the supported versions, see .NET Framework System Requirements.

.NET Framework

Supported in: 3.5, 3.0

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