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StackFrame::GetFileName Method ()
.NET Framework (current version)
Gets the file name that contains the code that is executing. This information is typically extracted from the debugging symbols for the executable.
Assembly: mscorlib (in mscorlib.dll)
The following example demonstrates the use of the GetFileName method. This code example is part of a larger example provided for the StackFrame class.
// Display the stack frame properties. StackFrame^ sf = st->GetFrame( i ); Console::WriteLine( " File: {0}", sf->GetFileName() ); Console::WriteLine( " Line Number: {0}", sf->GetFileLineNumber().ToString() ); // Note that the column number defaults to zero // when not initialized. Console::WriteLine( " Column Number: {0}", sf->GetFileColumnNumber().ToString() ); Console::WriteLine( " Intermediate Language Offset: {0}", sf->GetILOffset().ToString() ); Console::WriteLine( " Native Offset: {0}", sf->GetNativeOffset().ToString() );
FileIOPermission
for access to the path information. Associated enumeration: FileIOPermissionAccess
Universal Windows Platform
Available since 10
.NET Framework
Available since 1.1
Silverlight
Available since 2.0
Windows Phone Silverlight
Available since 7.0
Available since 10
.NET Framework
Available since 1.1
Silverlight
Available since 2.0
Windows Phone Silverlight
Available since 7.0
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