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StackFrame::GetFileName Method ()

 

Gets the file name that contains the code that is executing. This information is typically extracted from the debugging symbols for the executable.

Namespace:   System.Diagnostics
Assembly:  mscorlib (in mscorlib.dll)

public:
virtual String^ GetFileName()

Return Value

Type: System::String^

The file name, or null if the file name cannot be determined.

The following example demonstrates the use of the GetFileName method. This code example is part of a larger example provided for the StackFrame class.

// Display the stack frame properties.
StackFrame^ sf = st->GetFrame( i );
Console::WriteLine( " File: {0}", sf->GetFileName() );
Console::WriteLine( " Line Number: {0}", sf->GetFileLineNumber().ToString() );

// Note that the column number defaults to zero
// when not initialized.
Console::WriteLine( " Column Number: {0}", sf->GetFileColumnNumber().ToString() );
Console::WriteLine( " Intermediate Language Offset: {0}", sf->GetILOffset().ToString() );
Console::WriteLine( " Native Offset: {0}", sf->GetNativeOffset().ToString() );

FileIOPermission

for access to the path information. Associated enumeration: FileIOPermissionAccess

Universal Windows Platform
Available since 10
.NET Framework
Available since 1.1
Silverlight
Available since 2.0
Windows Phone Silverlight
Available since 7.0
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