And Method
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BitArray.And Method

[ This article is for Windows Phone 8 developers. If you’re developing for Windows 10, see the latest documentation. ]

Performs the bitwise AND operation on the elements in the current BitArray against the corresponding elements in the specified BitArray.

Namespace:  System.Collections
Assembly:  mscorlib (in mscorlib.dll)

public BitArray And(
	BitArray value
)

Parameters

value
Type: System.Collections.BitArray
The BitArray with which to perform the bitwise AND operation.

Return Value

Type: System.Collections.BitArray
A BitArray containing the result of the bitwise AND operation on the elements in the current BitArray against the corresponding elements in the specified BitArray.

ExceptionCondition
ArgumentNullException

value is null.

ArgumentException

value and the current BitArray do not have the same number of elements.

The bitwise AND operation returns true if both operands are true, and returns false if one or both operands are false.

This method is an O(n) operation, where n is Count.

The following code example shows how to apply AND to two BitArray instances.


using System;
using System.Collections;
public class Example
{

   public static void Demo(System.Windows.Controls.TextBlock outputBlock)
   {

      // Creates and initializes two BitArrays of the same size.
      BitArray myBA1 = new BitArray(4);
      BitArray myBA2 = new BitArray(4);
      myBA1[0] = myBA1[1] = false;
      myBA1[2] = myBA1[3] = true;
      myBA2[0] = myBA2[2] = false;
      myBA2[1] = myBA2[3] = true;

      // Performs a bitwise AND operation between BitArray instances of the same size.
      outputBlock.Text += "Initial values" + "\n";
      outputBlock.Text += "myBA1:";
      PrintValues(outputBlock, myBA1, 8);
      outputBlock.Text += "myBA2:";
      PrintValues(outputBlock, myBA2, 8);
      outputBlock.Text += "\n";

      outputBlock.Text += "Result" + "\n";
      outputBlock.Text += "AND:";
      PrintValues(outputBlock, myBA1.And(myBA2), 8);
      outputBlock.Text += "\n";

      outputBlock.Text += "After AND" + "\n";
      outputBlock.Text += "myBA1:";
      PrintValues(outputBlock, myBA1, 8);
      outputBlock.Text += "myBA2:";
      PrintValues(outputBlock, myBA2, 8);
      outputBlock.Text += "\n";

      // Performing AND between BitArray instances of different sizes returns an exception.
      try
      {
         BitArray myBA3 = new BitArray(8);
         myBA3[0] = myBA3[1] = myBA3[2] = myBA3[3] = false;
         myBA3[4] = myBA3[5] = myBA3[6] = myBA3[7] = true;
         myBA1.And(myBA3);
      }
      catch (Exception myException)
      {
         outputBlock.Text += "Exception: " + myException.ToString() + "\n";
      }
   }


   public static void PrintValues(System.Windows.Controls.TextBlock outputBlock, IEnumerable myList, int myWidth)
   {
      int i = myWidth;
      foreach (Object obj in myList)
      {
         if (i <= 0)
         {
            i = myWidth;
            outputBlock.Text += "\n";
         }
         i--;
         outputBlock.Text += String.Format("{0,8}", obj);
      }
      outputBlock.Text += "\n";
   }

}


/* 
This code produces the following output.

Initial values
myBA1:   False   False    True    True
myBA2:   False    True   False    True

Result
AND:   False   False   False    True

After AND
myBA1:   False   False   False    True
myBA2:   False    True   False    True

Exception: System.ArgumentException: Array lengths must be the same.
   at System.Collections.BitArray.And(BitArray value)
   at SamplesBitArray.Main()
*/


Windows Phone OS

Supported in: 8.1, 8.0, 7.1, 7.0

Windows Phone

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