Enumerable.Min<'TSource> Method (IEnumerable<'TSource>, Func<'TSource, Double>)
Invokes a transform function on each element of a sequence and returns the minimum Double value.
Assembly: System.Core (in System.Core.dll)
static member Min<'TSource> : source:IEnumerable<'TSource> * selector:Func<'TSource, float> -> float
A sequence of values to determine the minimum value of.
Return ValueType: System.Double
The minimum value in the sequence.
The type of the elements of source.
You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Double.
In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.
The following code example demonstrates how to use Min<'TSource>(IEnumerable<'TSource>, Func<'TSource, Int32>) to determine the minimum value in a sequence of projected values.
This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. To extend the example to this topic, change the body of the selector function.
Available since 4.5
Available since 3.5
Portable Class Library
Supported in: portable .NET platforms
Available since 2.0
Windows Phone Silverlight
Available since 7.0
Available since 8.1