Enumerable.Min Method (IEnumerable(Of Decimal))
[ This article is for Windows Phone 8 developers. If you’re developing for Windows 10, see the latest documentation. ]
Returns the minimum value in a sequence of Decimal values.
Assembly: System.Core (in System.Core.dll)
'Declaration <ExtensionAttribute> _ Public Shared Function Min ( _ source As IEnumerable(Of Decimal) _ ) As Decimal
Parameters
- source
- Type: System.Collections.Generic.IEnumerable(Of Decimal)
A sequence of Decimal values to determine the minimum value of.
Usage Note
In Visual Basic and C#, you can call this method as an instance method on any object of type IEnumerable(Of Decimal). When you use instance method syntax to call this method, omit the first parameter.| Exception | Condition |
|---|---|
| ArgumentNullException | source is Nothing. |
| InvalidOperationException | source contains no elements. |
The Min(IEnumerable(Of Decimal)) method uses the Decimal implementation of IComparable(Of T) to compare values.
In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Enumerable.Min.
The following code example demonstrates how to use Min(IEnumerable(Of Double)) to determine the minimum value in a sequence.
Note: |
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This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. To extend the example to this topic, substitute the elements of the source sequence with elements of the appropriate numerical type. |
' Create an array of double values.
Dim doubles() As Double = {1.5E+104, 9.0E+103, -2.0E+103}
' Determine the smallest number in the array.
Dim min As Double = doubles.Min()
' Display the result.
outputBlock.Text &= "The smallest number is " & min & vbCrLf
' This code produces the following output:
'
' The smallest number is -2E+103
Note: