Edit

OpCodes.Ceq Field

  • Reference

Definition

Namespace:
System.Reflection.Emit
Assembly:
System.Reflection.Primitives.dll
Assembly:
mscorlib.dll
Assembly:
netstandard.dll
Source:
OpCodes.cs
Source:
OpCodes.cs
Source:
OpCodes.cs

Compares two values. If they are equal, the integer value 1 (int32) is pushed onto the evaluation stack; otherwise 0 (int32) is pushed onto the evaluation stack.

public: static initonly System::Reflection::Emit::OpCode Ceq;
public static readonly System.Reflection.Emit.OpCode Ceq;
 staticval mutable Ceq : System.Reflection.Emit.OpCode
Public Shared ReadOnly Ceq As OpCode

Field Value

OpCode

Remarks

The following table lists the instruction's hexadecimal and Microsoft Intermediate Language (MSIL) assembly format, along with a brief reference summary:

Format Assembly Format Description
FE 01 ceq Pushes 1 if value1 equals value2; else pushes 0.

The stack transitional behavior, in sequential order, is:

  1. value1 is pushed onto the stack.

  2. value2 is pushed onto the stack.

  3. value2 and value1 are popped from the stack; value1 is compared to value2.

  4. If value1 is equal to value2, 1 is pushed onto the stack; otherwise 0 is pushed onto the stack.

The ceq instruction compares value1 and value2. If value1 is equal to value2, then 1 (of type int32) is pushed on the stack. Otherwise 0 (of type int32) is pushed on the stack.

For floating-point number, ceq will return 0 if the numbers are unordered (either or both are NaN). The infinite values are equal to themselves.

The following Emit method overload can use the ceq opcode:

Applies to