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C6282

warning C6282: Incorrect operator: assignment of constant in Boolean context. Consider using '==' instead

This warning indicates that an assignment of a constant to a variable was detected in a test context. Assignment of a constant to a variable in a test context is almost always incorrect. Replace the = with ==, or remove the assignment from the test context to resolve this warning.

Example

The following code generates this warning:

void f( int i )
{
   while (i = 5)
   {
   // code  
   }
}

To correct this warning, use the following code:

void f( int i )
{
   while (i == 5)
   {
   // code  
   }
}

See Also

Reference

Compiler Warning (level 4) C4706