Enumerable.Last(Of TSource) Method (IEnumerable(Of TSource), Func(Of TSource, Boolean))

Returns the last element of a sequence that satisfies a specified condition.

Namespace:  System.Linq
Assemblies:   System.Linq (in System.Linq.dll)
  System.Core (in System.Core.dll)

'Declaration
<ExtensionAttribute> _
Public Shared Function Last(Of TSource) ( _
	source As IEnumerable(Of TSource), _
	predicate As Func(Of TSource, Boolean) _
) As TSource

Type Parameters

TSource

The type of the elements of source.

Parameters

source
Type: System.Collections.Generic.IEnumerable(Of TSource)

An IEnumerable(Of T) to return an element from.

predicate
Type: System.Func(Of TSource, Boolean)

A function to test each element for a condition.

Return Value

Type: TSource
The last element in the sequence that passes the test in the specified predicate function.

Usage Note

In Visual Basic and C#, you can call this method as an instance method on any object of type IEnumerable(Of TSource). When you use instance method syntax to call this method, omit the first parameter. For more information, see Extension Methods (Visual Basic) or Extension Methods (C# Programming Guide).

ExceptionCondition
ArgumentNullException

source or predicate is Nothing.

InvalidOperationException

No element satisfies the condition in predicate.

-or-

The source sequence is empty.

The Last(Of TSource)(IEnumerable(Of TSource), Func(Of TSource, Boolean)) method throws an exception if no matching element is found in source. To instead return a default value when no matching element is found, use the LastOrDefault method.

The following code example demonstrates how to use Last(Of TSource)(IEnumerable(Of TSource), Func(Of TSource, Boolean)) to return the last element of an array that satisfies a condition.

        ' Create an array of integers. 
        Dim numbers() As Integer = _
            {9, 34, 65, 92, 87, 435, 3, 54, 83, 23, 87, 67, 12, 19}

        ' Get the last element in the array whose value is 
        ' greater than 80. 
        Dim last As Integer = numbers.Last(Function(num) num > 80)

        ' Display the result.
        MsgBox(last)

        ' This code produces the following output: 
        
        ' 87

.NET Framework

Supported in: 4.6, 4.5, 4, 3.5

.NET Framework Client Profile

Supported in: 4, 3.5 SP1

XNA Framework

Supported in: 3.0

.NET for Windows Phone apps

Supported in: Windows Phone 8.1, Windows Phone Silverlight 8.1, Windows Phone Silverlight 8

Portable Class Library

Supported in: Portable Class Library
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