Enumerable.Sum(TSource) Method (IEnumerable(TSource), Func(TSource, Int64))
Computes the sum of the sequence of Int64 values that are obtained by invoking a transform function on each element of the input sequence.
Assembly: System.Core (in System.Core.dll)
static member Sum : source:IEnumerable<'TSource> * selector:Func<'TSource, int64> -> int64
The type of the elements of source.
- Type: System.Collections.Generic.IEnumerable()
A sequence of values that are used to calculate a sum.
Return ValueType: System.Int64
The sum of the projected values.
Usage NoteIn Visual Basic and C#, you can call this method as an instance method on any object of type IEnumerable(). When you use instance method syntax to call this method, omit the first parameter. For more information, see Extension Methods (Visual Basic) or Extension Methods (C# Programming Guide).
This method returns zero if source contains no elements.
You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Int64.
In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.
The following code example demonstrates how to use Sum(TSource)(IEnumerable(TSource), Func(TSource, Double)) to sum the projected values of a sequence.
This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. To extend the example to this topic, change the body of the selector function.
Windows 7, Windows Vista SP1 or later, Windows XP SP3, Windows Server 2008 (Server Core not supported), Windows Server 2008 R2 (Server Core supported with SP1 or later), Windows Server 2003 SP2
The .NET Framework does not support all versions of every platform. For a list of the supported versions, see .NET Framework System Requirements.