Enumerable.Max Method (IEnumerable<Int64>)

Returns the maximum value in a sequence of Int64 values.

Namespace:  System.Linq
Assemblies:   System.Linq (in System.Linq.dll)
  System.Core (in System.Core.dll)

public static long Max(
	this IEnumerable<long> source
)

Parameters

source
Type: System.Collections.Generic.IEnumerable<Int64>

A sequence of Int64 values to determine the maximum value of.

Return Value

Type: System.Int64
The maximum value in the sequence.

Usage Note

In Visual Basic and C#, you can call this method as an instance method on any object of type IEnumerable<Int64>. When you use instance method syntax to call this method, omit the first parameter. For more information, see Extension Methods (Visual Basic) or Extension Methods (C# Programming Guide).

ExceptionCondition
ArgumentNullException

source is null.

InvalidOperationException

source contains no elements.

The Max(IEnumerable<Int64>) method uses the Int64 implementation of IComparable<T> to compare values.

In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

The following code example demonstrates how to use Max(IEnumerable<Int64>) to determine the maximum value in a sequence.

            List<long> longs = new List<long> { 4294967296L, 466855135L, 81125L };

            long max = longs.Max();

            Console.WriteLine("The largest number is {0}.", max);

            /*
             This code produces the following output:

             The largest number is 4294967296.
            */

.NET Framework

Supported in: 4.6, 4.5, 4, 3.5

.NET Framework Client Profile

Supported in: 4, 3.5 SP1

XNA Framework

Supported in: 3.0

Portable Class Library

Supported in: Portable Class Library

Supported in: Windows Phone 8.1

Supported in: Windows Phone Silverlight 8.1

Supported in: Windows Phone Silverlight 8
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