Enumerable.Min Method (IEnumerable<Nullable<Decimal>>)


Returns the minimum value in a sequence of nullable Decimal values.

Namespace:   System.Linq
Assembly:  System.Core (in System.Core.dll)

public static Nullable<decimal> Min(
	this IEnumerable<Nullable<decimal>> source


Type: System.Collections.Generic.IEnumerable<Nullable<Decimal>>

A sequence of nullable Decimal values to determine the minimum value of.

Return Value

Type: System.Nullable<Decimal>

A value of type Nullable<Decimal> in C# or Nullable(Of Decimal) in Visual Basic that corresponds to the minimum value in the sequence.

Exception Condition

source is null.

The Min(IEnumerable<Nullable<Decimal>>) method uses the Decimal implementation of IComparable<T> to compare values.

If the source sequence is empty or contains only values that are null, this function returns null.

In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

The following code example demonstrates how to use Min(IEnumerable<Nullable<Int32>>) to determine the minimum value in a sequence.


This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. To extend the example to this topic, substitute the elements of the source sequence with elements of the appropriate numerical type.

int?[] grades = { 78, 92, null, 99, 37, 81 };

int? min = grades.Min();

Console.WriteLine("The lowest grade is {0}.", min);

 This code produces the following output:

 The lowest grade is 37.

Universal Windows Platform
Available since 4.5
.NET Framework
Available since 3.5
Portable Class Library
Supported in: portable .NET platforms
Available since 2.0
Windows Phone Silverlight
Available since 7.0
Windows Phone
Available since 8.1
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