XMVector4Less method
Tests whether one 4D vector is less than another 4D vector.
Syntax
bool XMVector4Less( [in] XMVECTOR V1, [in] XMVECTOR V2 );
Parameters
- V1 [in]
-
4D vector.
- V2 [in]
-
4D vector.
Return value
Returns true if V1 is less than V2 and false otherwise. See the remarks section.
Remarks
The following pseudocode demonstrates the operation of the function:
return ( V1.x < V2.x && V1.y < V2.y &&
V1.z < V2.z && V1.w < V2.w );
Platform Requirements
Microsoft Visual Studio 2010 or Microsoft Visual Studio 2012 with the Windows SDK for Windows 8. Supported for Win32 desktop apps, Windows Store apps, and Windows Phone 8 apps.
Requirements
|
Namespace |
Use DirectX. |
|---|---|
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Header |
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See also
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