Color.FromArgb Method (Byte, Byte, Byte, Byte)


Creates a new Color structure by using the specified sRGB alpha channel and color channel values.

Namespace:   System.Windows.Media
Assembly:  PresentationCore (in PresentationCore.dll)

Public Shared Function FromArgb (
	a As Byte,
	r As Byte,
	g As Byte,
	b As Byte
) As Color


Type: System.Byte

The alpha channel, A, of the new color.

Type: System.Byte

The red channel, R, of the new color.

Type: System.Byte

The green channel, G, of the new color.

Type: System.Byte

The blue channel, B, of the new color.

Return Value

Type: System.Windows.Media.Color

A Color structure with the specified values.

The FromArgb method allows you to specify the alpha channel; the FromRgb method uses a default value of 255 for the alpha channel.

The alpha channel of a color determines the amount of transparency of the color. An alpha value of 255 indicates that the color is completely opaque, and a value of 0 indicates that the color is completely transparent.

Private Function FromArgbExample() As Color
	' Create a blue color using the FromArgb static method.
	Dim myArgbColor As New Color()
	myArgbColor = Color.FromArgb(255, 0, 255, 0)
	Return myArgbColor
End Function

.NET Framework
Available since 3.0
Available since 2.0
Windows Phone Silverlight
Available since 7.0
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