MenuItem.PerformClick Method ()


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Generates a Click event for the MenuItem, simulating a click by a user.

Namespace:   System.Windows.Forms
Assembly:  System.Windows.Forms (in System.Windows.Forms.dll)

public void PerformClick()

You can use this menu to activate a menu item through code without passing any event information. For example, if you want to activate a menu item based on an action that occurs in your application, you can call the PerformClick method for that MenuItem.

In this example you programmatically click a menu item by using the PerformClick method. First, you create a main menu (mainMenu1) and add to it two menu items, menuItem1 (File) and menuItem2 (Edit). You also use the Click event to send data to the event handler when a menu item is clicked. Then you use the PerformClick method to click the File menu item. When you start the application, the File menu item is activated, and a message box that contains the text "The File menu is clicked." appears on the screen. The example requires that you have created a Form named Form1.

public void CreateMyMenu()
	// Create a main menu object.
	MainMenu mainMenu1 = new MainMenu();

	// Create empty menu item objects.
	MenuItem menuItem1 = new MenuItem();
	MenuItem menuItem2 = new MenuItem();

	// Set the caption of the menu items.
	menuItem1.Text = "&File";
	menuItem2.Text = "&Edit";

	// Add the menu items to the main menu.

	// Add functionality to the menu items. 
	menuItem1.Click += new System.EventHandler(this.menuItem1_Click);
	menuItem2.Click += new System.EventHandler(this.menuItem2_Click);

	// Assign mainMenu1 to the form.

	// Perform a click on the File menu item.

private void menuItem1_Click(object sender, System.EventArgs e)
	MessageBox.Show("You clicked the File menu.","The Event Information");		

private void menuItem2_Click(object sender, System.EventArgs e)
	MessageBox.Show("You clicked the Edit menu.","The Event Information");		

.NET Framework
Available since 1.1
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