MenuItem::Parent Property
.NET Framework (current version)
Gets a value indicating the menu that contains this menu item.
Assembly: System.Windows.Forms (in System.Windows.Forms.dll)
In this example, you create a main menu and a top-level menu item, menuItem1 (File). You also create two menu items, menuItem2 (New) and menuItem3 (Open), and add them to the menu item list of menuItem1. Then you check to see if menuItem3 has got a parent menu, which is true, and display the information of this parent menu in message box. This example requires that you have created a Form named Form1.
public: void CreateMyMenuItems() { // Craete a main menu object. MainMenu^ mainMenu1 = gcnew MainMenu; // Create three top-level menu items. MenuItem^ menuItem1 = gcnew MenuItem( "&File" ); MenuItem^ menuItem2 = gcnew MenuItem( "&New" ); MenuItem^ menuItem3 = gcnew MenuItem( "&Open" ); // Add menuItem1 to the main menu. mainMenu1->MenuItems->Add( menuItem1 ); // Add menuItem2 and menuItem3 to menuItem1. menuItem1->MenuItems->Add( menuItem2 ); menuItem1->MenuItems->Add( menuItem3 ); // Check to see if menuItem3 has a parent menu. if ( menuItem3->Parent != nullptr ) MessageBox::Show( String::Concat( menuItem3->Parent, "." ), "Parent Menu Information of menuItem3" ); else MessageBox::Show( "No parent menu." ); // Assign mainMenu1 to the form. this->Menu = mainMenu1; }
.NET Framework
Available since 1.1
Available since 1.1
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