ContextMenu.SourceControl Property

 

Gets the control that is displaying the shortcut menu.

Namespace:   System.Windows.Forms
Assembly:  System.Windows.Forms (in System.Windows.Forms.dll)

[BrowsableAttribute(false)]
public Control SourceControl {
	[UIPermissionAttribute(SecurityAction.Demand, Window = UIPermissionWindow.AllWindows)]
	get;
}

Property Value

Type: System.Windows.Forms.Control

A Control that represents the control that is displaying the shortcut menu. If no control has displayed the shortcut menu, the property returns null.

This property enables you to determine which control currently displays the shortcut menu defined in the ContextMenu. If the shortcut menu is not currently displayed, you can use this property to determine which control last displayed the shortcut menu. You can use this property in the Popup event to ensure that the control displays the proper menu items. You can also use this property to pass a reference to the control to a method that performs the tasks associated with a menu command displayed in the shortcut menu. Since the Form class inherits from Control, you can also use this property if the ContextMenu is associated with a form.

The following code example creates an event handler for the Popup event of the ContextMenu. The code in the event handler determines which of two controls a PictureBox named pictureBox1 and a TextBox named textBox1 is the control displaying the shortcut menu. Depending on which control caused the ContextMenu to display its shortcut menu, the control adds the appropriate MenuItem objects to the ContextMenu. This example requires that you have an instance of the ContextMenu class, named contextMenu1, defined within the form. This example also requires that you have a TextBox and PictureBox added to a form and that the ContextMenu property of these controls is set to contextMenu1.

private void MyPopupEventHandler(System.Object sender, System.EventArgs e)
 {
    // Define the MenuItem objects to display for the TextBox.
    MenuItem menuItem1 = new MenuItem("&Copy");
    MenuItem menuItem2 = new MenuItem("&Find and Replace");
    // Define the MenuItem object to display for the PictureBox.
    MenuItem menuItem3 = new MenuItem("C&hange Picture");

    // Clear all previously added MenuItems.
    contextMenu1.MenuItems.Clear();

    if(contextMenu1.SourceControl == textBox1)
    {
       // Add MenuItems to display for the TextBox.
       contextMenu1.MenuItems.Add(menuItem1);
       contextMenu1.MenuItems.Add(menuItem2);
    }
    else if(contextMenu1.SourceControl == pictureBox1)
    {
       // Add the MenuItem to display for the PictureBox.
       contextMenu1.MenuItems.Add(menuItem3);
    }
 }

.NET Framework
Available since 1.1
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