MetaModel.GetModel Method (Type)

 

Returns the data-model instance for the specified context.

Namespace:   System.Web.DynamicData
Assembly:  System.Web.DynamicData (in System.Web.DynamicData.dll)

public static MetaModel GetModel(
	Type contextType
)

Parameters

contextType
Type: System.Type

The type of the data context as defined in the data model.

Return Value

Type: System.Web.DynamicData.MetaModel

The data model that is associated with the specified context type.

The following example shows how to use the GetModel(Type) method to perform the following tasks:

  • Getting the default data model.

  • Getting the data model specified by the passed context type.

For a complete example, see the MetaModel class overview.

// Get the data model. 
public MetaModel GetModel(bool defaultModel)
{
    MetaModel model;

    if (defaultModel)
        model = MetaModel.Default;
    else
        model =
           MetaModel.GetModel(typeof(AdventureWorksLTDataContext));
    return model;
}

.NET Framework
Available since 3.5
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