BigInteger.Remainder Method

Performs integer division on two BigInteger values and returns the remainder.

Namespace:  System.Numerics
Assembly:  System.Numerics (in System.Numerics.dll)

public static BigInteger Remainder(
	BigInteger dividend,
	BigInteger divisor


Type: System.Numerics.BigInteger
The value to be divided.
Type: System.Numerics.BigInteger
The value to divide by.

Return Value

Type: System.Numerics.BigInteger
The remainder after dividing dividend by divisor.


divisor is 0 (zero).

The sign of the remainder is the sign of the dividend parameter.

The Remainder method is implemented for languages that do not support custom operators. Its behavior is identical to division using the modulus operator.

If necessary, the method automatically performs implicit conversion of other integral types to BigInteger objects before it performs the modulus operation.

The following example compares the remainder from the DivRem method with the remainder returned by the Remainder method to establish that the two methods calculate identical remainders.

using System;
using System.Numerics;

public class Example
   public static void Demo(System.Windows.Controls.TextBlock outputBlock)
      BigInteger dividend1 = BigInteger.Pow(Int64.MaxValue, 3);
      BigInteger dividend2 = dividend1 * BigInteger.MinusOne;
      BigInteger divisor1 = Int32.MaxValue;
      BigInteger divisor2 = divisor1 * BigInteger.MinusOne;
      BigInteger remainder1, remainder2;
      BigInteger divRem1 = BigInteger.Zero;
      BigInteger divRem2 = BigInteger.Zero;

      remainder1 = BigInteger.Remainder(dividend1, divisor1);
      remainder2 = BigInteger.Remainder(dividend2, divisor1);

      BigInteger.DivRem(dividend1, divisor1, out divRem1);
      outputBlock.Text += String.Format("BigInteger.Remainder({0}, {1}) = {2}",
                        dividend1, divisor1, remainder1) + "\n";
      outputBlock.Text += String.Format("BigInteger.DivRem({0}, {1}) = {2}",
                        dividend1, divisor1, divRem1) + "\n";
      if (remainder1.Equals(divRem1))
         outputBlock.Text += "The remainders are equal.\n" + "\n";

      BigInteger.DivRem(dividend2, divisor2, out divRem2);
      outputBlock.Text += String.Format("BigInteger.Remainder({0}, {1}) = {2}",
                        dividend2, divisor2, remainder2) + "\n";
      outputBlock.Text += String.Format("BigInteger.DivRem({0}, {1}) = {2}",
                        dividend2, divisor2, divRem2) + "\n";
      if (remainder2.Equals(divRem2))
         outputBlock.Text += "The remainders are equal.\n" + "\n";
// The example displays the following output:
//    BigInteger.Remainder(7.8463771692333509522426190271E+56, 2147483647) = 1
//    BigInteger.DivRem(7.8463771692333509522426190271E+56, 2147483647) = 1
//    The remainders are equal.
//    BigInteger.Remainder(-7.8463771692333509522426190271E+56, -2147483647) = -1
//    BigInteger.DivRem(-7.8463771692333509522426190271E+56, -2147483647) = -1
//    The remainders are equal.


Supported in: 5, 4

For a list of the operating systems and browsers that are supported by Silverlight, see Supported Operating Systems and Browsers.

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