# Math.Log10 Method

.NET Framework 3.0
Returns the base 10 logarithm of a specified number.

Namespace: System
Assembly: mscorlib (in mscorlib.dll)

## Syntax

```public static double Log10 (
double d
)
```
```public static double Log10 (
double d
)
```
```public static function Log10 (
d : double
) : double
```
```Not applicable.
```

#### Parameters

d

A number whose logarithm is to be found.

#### Return Value

Sign of d

Returns

Positive

The base 10 log of d; that is, log 10d.

Zero

Negative

If d is equal to NaN, this method returns NaN. If d is equal to PositiveInfinity, this method returns PositiveInfinity.

## Remarks

Parameter d is specified as a base 10 number.

## Example

The following example uses Log10 to evaluate certain logarithmic identities for selected values.

```// Example for the Math.Log( double, double ) and Math.Log10( double ) methods.
using System;

class LogDDLog10
{
public static void Main()
{
Console.WriteLine(
"This example of Math.Log( double, double ) " +
"and Math.Log10( double )\n" +
"generates the following output.\n" );
Console.WriteLine(
"Evaluate these identities with " +
"selected values for X and B (base):" );
Console.WriteLine( "   log(B)[X] == 1 / log(X)[B]" );
Console.WriteLine( "   log(B)[X] == log(10)[X] / log(10)[B]" );
Console.WriteLine( "   log(B)[X] == log(B)[10] * log(10)[X]" );

UseBaseAndArg(0.1, 1.2);
UseBaseAndArg(1.2, 4.9);
UseBaseAndArg(4.9, 9.9);
UseBaseAndArg(9.9, 0.1);
}

// Evaluate logarithmic identities that are functions of two arguments.
static void UseBaseAndArg(double argB, double argX)
{
// Evaluate log(B)[X] == 1 / log(X)[B].
Console.WriteLine(
"\n                   Math.Log({1}, {0}) == {2:E16}" +
"\n             1.0 / Math.Log({0}, {1}) == {3:E16}",
argB, argX, Math.Log(argX, argB),
1.0 / Math.Log(argB, argX) );

// Evaluate log(B)[X] == log(10)[X] / log(10)[B].
Console.WriteLine(
"    Math.Log10({1}) / Math.Log10({0}) == {2:E16}",
argB, argX, Math.Log10(argX) / Math.Log10(argB) );

// Evaluate log(B)[X] == log(B)[10] * log(10)[X].
Console.WriteLine(
"Math.Log(10.0, {0}) * Math.Log10({1}) == {2:E16}",
argB, argX, Math.Log(10.0, argB) * Math.Log10(argX) );
}
}

/*
This example of Math.Log( double, double ) and Math.Log10( double )
generates the following output.

Evaluate these identities with selected values for X and B (base):
log(B)[X] == 1 / log(X)[B]
log(B)[X] == log(10)[X] / log(10)[B]
log(B)[X] == log(B)[10] * log(10)[X]

Math.Log(1.2, 0.1) == -7.9181246047624818E-002
1.0 / Math.Log(0.1, 1.2) == -7.9181246047624818E-002
Math.Log10(1.2) / Math.Log10(0.1) == -7.9181246047624818E-002
Math.Log(10.0, 0.1) * Math.Log10(1.2) == -7.9181246047624831E-002

Math.Log(4.9, 1.2) == 8.7166610085093179E+000
1.0 / Math.Log(1.2, 4.9) == 8.7166610085093161E+000
Math.Log10(4.9) / Math.Log10(1.2) == 8.7166610085093179E+000
Math.Log(10.0, 1.2) * Math.Log10(4.9) == 8.7166610085093179E+000

Math.Log(9.9, 4.9) == 1.4425396251981288E+000
1.0 / Math.Log(4.9, 9.9) == 1.4425396251981288E+000
Math.Log10(9.9) / Math.Log10(4.9) == 1.4425396251981288E+000
Math.Log(10.0, 4.9) * Math.Log10(9.9) == 1.4425396251981291E+000

Math.Log(0.1, 9.9) == -1.0043839404494075E+000
1.0 / Math.Log(9.9, 0.1) == -1.0043839404494075E+000
Math.Log10(0.1) / Math.Log10(9.9) == -1.0043839404494077E+000
Math.Log(10.0, 9.9) * Math.Log10(0.1) == -1.0043839404494077E+000
*/

```
```// Example for the Math.Log( double, double ) and Math.Log10( double ) methods.
import System.*;

class LogDDLog10
{
public static void main(String[] args)
{
Console.WriteLine(("This example of Math.Log( double, double ) "
+ "and Math.Log10( double )\n"
+ "generates the following output.\n"));
Console.WriteLine(("Evaluate these identities with "
+ "selected values for X and B (base):"));
Console.WriteLine("   log(B)[X] == 1 / log(X)[B]");
Console.WriteLine("   log(B)[X] == log(10)[X] / log(10)[B]");
Console.WriteLine("   log(B)[X] == log(B)[10] * log(10)[X]");
UseBaseAndArg(0.1, 1.2);
UseBaseAndArg(1.2, 4.9);
UseBaseAndArg(4.9, 9.9);
UseBaseAndArg(9.9, 0.1);
} //main

// Evaluate logarithmic identities that are functions of two arguments.
static void UseBaseAndArg(double argB, double argX)
{
// Evaluate log(B)[X] == 1 / log(X)[B].
Console.WriteLine("\n                   Math.Log({1}, {0}) == {2}"
+ "\n             1.0 / Math.Log({0}, {1}) == {3}",
new Object[]{ System.Convert.ToString(argB),
System.Convert.ToString(argX),((System.Double)(
System.Math.Log(argX, argB))).ToString("E16"),
((System.Double)(1.0 / System.Math.Log(argB, argX)))
.ToString("E16")});

// Evaluate log(B)[X] == log(10)[X] / log(10)[B].
Console.WriteLine("    Math.Log10({1}) / Math.Log10({0}) == {2}",
System.Convert.ToString(argB),
System.Convert.ToString(argX),
((System.Double)(System.Math.Log10(argX) /
System.Math.Log10(argB))).ToString("E16"));

// Evaluate log(B)[X] == log(B)[10] * log(10)[X].
Console.WriteLine("Math.Log(10.0, {0}) * Math.Log10({1}) == {2}",
System.Convert.ToString(argB),
System.Convert.ToString(argX),
((System.Double) (System.Math.Log(10.0, argB)
* System.Math.Log10(argX))).ToString("E16") );
} //UseBaseAndArg
} //LogDDLog10

/*
This example of Math.Log( double, double ) and Math.Log10( double )
generates the following output.

Evaluate these identities with selected values for X and B (base):
log(B)[X] == 1 / log(X)[B]
log(B)[X] == log(10)[X] / log(10)[B]
log(B)[X] == log(B)[10] * log(10)[X]

Math.Log(1.2, 0.1) == -7.9181246047624818E-002
1.0 / Math.Log(0.1, 1.2) == -7.9181246047624818E-002
Math.Log10(1.2) / Math.Log10(0.1) == -7.9181246047624818E-002
Math.Log(10.0, 0.1) * Math.Log10(1.2) == -7.9181246047624831E-002

Math.Log(4.9, 1.2) == 8.7166610085093179E+000
1.0 / Math.Log(1.2, 4.9) == 8.7166610085093161E+000
Math.Log10(4.9) / Math.Log10(1.2) == 8.7166610085093179E+000
Math.Log(10.0, 1.2) * Math.Log10(4.9) == 8.7166610085093179E+000

Math.Log(9.9, 4.9) == 1.4425396251981288E+000
1.0 / Math.Log(4.9, 9.9) == 1.4425396251981288E+000
Math.Log10(9.9) / Math.Log10(4.9) == 1.4425396251981288E+000
Math.Log(10.0, 4.9) * Math.Log10(9.9) == 1.4425396251981291E+000

Math.Log(0.1, 9.9) == -1.0043839404494075E+000
1.0 / Math.Log(9.9, 0.1) == -1.0043839404494075E+000
Math.Log10(0.1) / Math.Log10(9.9) == -1.0043839404494077E+000
Math.Log(10.0, 9.9) * Math.Log10(0.1) == -1.0043839404494077E+000
*/

```

## Platforms

Windows 98, Windows Server 2000 SP4, Windows CE, Windows Millennium Edition, Windows Mobile for Pocket PC, Windows Mobile for Smartphone, Windows Server 2003, Windows XP Media Center Edition, Windows XP Professional x64 Edition, Windows XP SP2, Windows XP Starter Edition

The Microsoft .NET Framework 3.0 is supported on Windows Vista, Microsoft Windows XP SP2, and Windows Server 2003 SP1.

## Version Information

#### .NET Framework

Supported in: 3.0, 2.0, 1.1, 1.0

#### .NET Compact Framework

Supported in: 2.0, 1.0

#### XNA Framework

Supported in: 1.0