DateSeparator Property

DateTimeFormatInfo.DateSeparator Property


Gets or sets the string that separates the components of a date, that is, the year, month, and day.

Namespace:   System.Globalization
Assembly:  mscorlib (in mscorlib.dll)

public string DateSeparator { get; set; }

Property Value

Type: System.String

The string that separates the components of a date, that is, the year, month, and day. The default for InvariantInfo is "/".

Exception Condition

The property is being set to null.


The property is being set and the DateTimeFormatInfo object is read-only.

If a custom format string includes the "/" format specifier, the DateTime.ToString method displays the value of DateSeparator in place of the "/" in the result string.

The DateSeparator property defines the string that replaces the date separator ("/" custom date and time format specifier) in a result string in a formatting operation. It also defines the date separator string in a parsing operation.

The following example instantiates a CultureInfo object for the en-US culture, changes its date separator to "-", and displays a date by using the "d", "G", and "g" standard format strings.

using System;
using System.Globalization;

public class Example
   public static void Main()
      DateTime value = new DateTime(2013, 9, 8);

      string[] formats = { "d", "G", "g" };
      CultureInfo culture = CultureInfo.CreateSpecificCulture("en-US");
      DateTimeFormatInfo dtfi = culture.DateTimeFormat;
      dtfi.DateSeparator = "-";

      foreach (var fmt in formats)
         Console.WriteLine("{0}: {1}", fmt, value.ToString(fmt, dtfi));
// The example displays the following output:
//       d: 9-8-2013
//       G: 9-8-2013 12:00:00 AM
//       g: 9-8-2013 12:00 AM

.NET Framework
Available since 1.1
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