Compiler Warning (level 2) C4307 (Windows CE 5.0)
'operator' : integral constant overflow
The operator is used in an expression that results in an integer constant overflowing the space allocated for it. You may need to use a larger type for the constant. A signed int holds a smaller value than an unsigned int because the signed int uses one bit to represent the sign.
The following example shows how this message might occur.
int i = 2000000000 + 2000000000; // warning
int j = (unsigned)2000000000 + 2000000000; // OK
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