For the latest documentation on Visual Studio 2017 RC, see Visual Studio 2017 RC Documentation.
void * _aligned_recalloc( void *memblock, size_t num, size_t size, size_t alignment );
The current memory block pointer.
The number of elements.
The size in bytes of each element.
The alignment value, which must be an integer power of 2.
_aligned_recalloc returns a void pointer to the reallocated (and possibly moved) memory block. The return value is
NULL if the size is zero and the buffer argument is not
NULL, or if there is not enough available memory to expand the block to the given size. In the first case, the original block is freed. In the second case, the original block is unchanged. The return value points to a storage space that is guaranteed to be suitably aligned for storage of any type of object. To get a pointer to a type other than void, use a type cast on the return value.
It is an error to reallocate memory and change the alignment of a block.
_aligned_recalloc is based on
malloc. For more information about using
_aligned_offset_malloc, see malloc.
This function sets
ENOMEM if the memory allocation failed or if the requested size was greater than
_HEAP_MAXREQ. For more information about
errno, see errno, _doserrno, _sys_errlist, and _sys_nerr. Also,
_aligned_recalloc validates its parameters. If
alignment is not a power of 2, this function invokes the invalid parameter handler, as described in Parameter Validation. If execution is allowed to continue, this function returns
NULL and sets
Not applicable. To call the standard C function, use
PInvoke. For more information, see Platform Invoke Examples.