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XmlReader.ReadElementContentAsDateTime Method

Reads the current element and returns the contents as a DateTime object.

Namespace:  System.Xml
Assembly:  System.Xml (in System.Xml.dll)

Public Overridable Function ReadElementContentAsDateTime As DateTime

Return Value

Type: System.DateTime
The element content as a DateTime object.


The XmlReader is not positioned on an element.


The current element contains child elements.


The element content cannot be converted to a DateTime object.


The method is called with Nothing arguments.

This method reads the start tag, the contents of the element, and moves the reader past the end element tag. It expands entities and ignores processing instructions and comments. The element can only contain simple content. That is, it cannot have child elements.

Dim output As New StringBuilder()

Dim xmlString As String = _
            "<root>" & _
            "<stringValue><!--comment-->" & _
            "<?some pi?>text value of the element." & _
            "</stringValue>" & _
            "<longValue>270000000000001</longValue><number>0</number>" & _
            "<double>2E10</double><date>2003-01-08T15:00:00-00:00</date>" & _

Using reader As XmlReader = XmlReader.Create(New StringReader(xmlString))

    Dim [date] As DateTime = reader.ReadElementContentAsDateTime()

    ' If the current culture is "en-US",
    ' this writes "Wednesday, January 8, 2003".

    OutputTextBlock.Text = output.ToString()
End Using


Supported in: 5, 4, 3

Silverlight for Windows Phone

Supported in: Windows Phone OS 7.1, Windows Phone OS 7.0

XNA Framework

Supported in: Xbox 360, Windows Phone OS 7.0

For a list of the operating systems and browsers that are supported by Silverlight, see Supported Operating Systems and Browsers.

Community Additions

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