Compiler Warning (level 3) C4334

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'operator' : result of 32-bit shift implicitly converted to 64 bits (was 64-bit shift intended?)

The result of 32-bit shift was implicitly converted to 64-bits, and the compiler suspects that a 64-bit shift was intended. To resolve this warning, either use 64-bit shift, or explicitly cast the shift result to 64-bit.

Example

The following sample generates C4334.

// C4334.cpp
// compile with: /W3 /c
void SetBit(unsigned __int64 *p, int i) {
   *p |= (1 << i);   // C4334
   *p |= (1i64 << i);   // OK
}