Array::LastIndexOf Method (Array^, Object^, Int32)

 

Searches for the specified object and returns the index of the last occurrence within the range of elements in the one-dimensional Array that extends from the first element to the specified index.

Namespace:   System
Assembly:  mscorlib (in mscorlib.dll)

public:
static int LastIndexOf(
	Array^ array,
	Object^ value,
	int startIndex
)

Parameters

array
Type: System::Array^

The one-dimensional Array to search.

value
Type: System::Object^

The object to locate in array.

startIndex
Type: System::Int32

The starting index of the backward search.

Return Value

Type: System::Int32

The index of the last occurrence of value within the range of elements in array that extends from the first element to startIndex, if found; otherwise, the lower bound of the array minus 1.

Exception Condition
ArgumentNullException

array is null.

ArgumentOutOfRangeException

startIndex is outside the range of valid indexes for array.

RankException

array is multidimensional.

The one-dimensional Array is searched backward starting at startIndex and ending at the first element.

The elements are compared to the specified value using the Object::Equals method. If the element type is a nonintrinsic (user-defined) type, the Equals implementation of that type is used.

Since most arrays will have a lower bound of zero, this method would generally return –1 when value is not found. In the rare case that the lower bound of the array is equal to Int32::MinValue and value is not found, this method returns Int32::MaxValue, which is System.Int32.MinValue - 1.

This method is an O(n) operation, where n is the number of elements from the beginning of array to startIndex.

In the .NET Framework version 2.0, this method uses the Equals and CompareTo methods of the Array to determine whether the Object specified by the value parameter exists. In the earlier versions of the .NET Framework, this determination was made by using the Equals and CompareTo methods of the valueObject itself.

The following code example shows how to determine the index of the last occurrence of a specified element in an array.

using namespace System;
void PrintIndexAndValues( Array^ myArray );

void main()
{
   // Creates and initializes a new Array instance with three elements of the same value.
   Array^ myArray = Array::CreateInstance( String::typeid, 12 );
   myArray->SetValue( "the", 0 );
   myArray->SetValue( "quick", 1 );
   myArray->SetValue( "brown", 2 );
   myArray->SetValue( "fox", 3 );
   myArray->SetValue( "jumped", 4 );
   myArray->SetValue( "over", 5 );
   myArray->SetValue( "the", 6 );
   myArray->SetValue( "lazy", 7 );
   myArray->SetValue( "dog", 8 );
   myArray->SetValue( "in", 9 );
   myArray->SetValue( "the", 10 );
   myArray->SetValue( "barn", 11 );

   // Displays the values of the Array.
   Console::WriteLine(  "The Array instance contains the following values:" );
   PrintIndexAndValues( myArray );

   // Searches for the last occurrence of the duplicated value.
   String^ myString =  "the";
   int myIndex = Array::LastIndexOf( myArray, myString );
   Console::WriteLine(  "The last occurrence of \"{0}\" is at index {1}.", myString, myIndex );

   // Searches for the last occurrence of the duplicated value in the first section of the Array.
   myIndex = Array::LastIndexOf( myArray, myString, 8 );
   Console::WriteLine(  "The last occurrence of \"{0}\" between the start and index 8 is at index {1}.", myString, myIndex );

   // Searches for the last occurrence of the duplicated value in a section of the Array.  
   // Note that the start index is greater than the end index because the search is done backward.
   myIndex = Array::LastIndexOf( myArray, myString, 10, 6 );
   Console::WriteLine(  "The last occurrence of \"{0}\" between index 5 and index 10 is at index {1}.", myString, myIndex );
}

void PrintIndexAndValues( Array^ myArray )
{
   for ( int i = myArray->GetLowerBound( 0 ); i <= myArray->GetUpperBound( 0 ); i++ )
      Console::WriteLine(  "\t[{0}]:\t{1}", i, myArray->GetValue( i ) );
}

/* 
 This code produces the following output.

 The Array instance contains the following values:
     [0]:    the
     [1]:    quick
     [2]:    brown
     [3]:    fox
     [4]:    jumped
     [5]:    over
     [6]:    the
     [7]:    lazy
     [8]:    dog
     [9]:    in
     [10]:    the
     [11]:    barn
 The last occurrence of "the" is at index 10.
 The last occurrence of "the" between the start and index 8 is at index 6.
 The last occurrence of "the" between index 5 and index 10 is at index 10.
 */

Universal Windows Platform
Available since 8
.NET Framework
Available since 1.1
Portable Class Library
Supported in: portable .NET platforms
Windows Phone Silverlight
Available since 8.0
Windows Phone
Available since 8.1
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