Font Constructor (Font, FontStyle)


Initializes a new Font that uses the specified existing Font and FontStyle enumeration.

Namespace:   System.Drawing
Assembly:  System.Drawing (in System.Drawing.dll)

Public Sub New (
	prototype As Font,
	newStyle As FontStyle


Type: System.Drawing.Font

The existing Font from which to create the new Font.

Type: System.Drawing.FontStyle

The FontStyle to apply to the new Font. Multiple values of the FontStyle enumeration can be combined with the OR operator.

For localized applications that are based on the .NET Framework 2.0 and earlier releases, specifying a font for prototype when that font has not been installed on the computer that is used to build your application will cause the Microsoft Sans Serif font to be used instead. If your application depends on this behavior and you must recompile your application for the .NET Framework 3.0, you should specify the Microsoft Sans Serif font for prototype.

The following code example demonstrates the Inequality operator, the Font constructor, and the Bold property. This example is designed to be used with a Windows Form that contains a button named Button2. Paste the following code into your form and associate the Button2_Click method with the button's Click event.

Private Sub Button2_Click(ByVal sender As System.Object, _
    ByVal e As System.EventArgs) Handles Button2.Click

    If (Color.op_Inequality(Me.BackColor, SystemColors.ControlDark)) Then
        Me.BackColor = SystemColors.ControlDark
    End If
    If Not (Me.Font.Bold) Then
        Me.Font = New Font(Me.Font, FontStyle.Bold)
    End If
End Sub

.NET Framework
Available since 1.1
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