Enumerable.Min<'TSource> Method (IEnumerable<'TSource>, Func<'TSource, Int32>)

.NET Framework (current version)

Invokes a transform function on each element of a sequence and returns the minimum Int32 value.

Namespace: System.Linq
Assembly: System.Core (in System.Core.dll)

Syntax

static member Min<'TSource> : 
        source:IEnumerable<'TSource> *
        selector:Func<'TSource, int> -> int

Parameters

source: Type: System.Collections.Generic.IEnumerable<'TSource>
A sequence of values to determine the minimum value of.

selector: Type: System.Func<'TSource, Int32>
A transform function to apply to each element.

Return Value

Type: System.Int32

The minimum value in the sequence.

Type Parameters

TSource: The type of the elements of source.

Exceptions

Exception	Condition
ArgumentNullException	source or selector is null.
InvalidOperationException	source contains no elements.

Remarks

The Min<'TSource>(IEnumerable<'TSource>, Func<'TSource, Int32>) method uses the Int32 implementation of IComparable<'T> to compare values.

You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Int32.

In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

Examples

The following code example demonstrates how to use Min<'TSource>(IEnumerable<'TSource>, Func<'TSource, Int32>) to determine the minimum value in a sequence of projected values.

No code example is currently available or this language may not be supported.

Universal Windows Platform
Available since 8
.NET Framework
Available since 3.5
Portable Class Library
Supported in: portable .NET platforms
Silverlight
Available since 2.0
Windows Phone Silverlight
Available since 7.0
Windows Phone
Available since 8.1