Max(TSource) Method (IEnumerable(TSource), Func(TSource, Double))

Enumerable::Max<TSource> Method (IEnumerable<TSource>^, Func<TSource, Double>^)


Invokes a transform function on each element of a sequence and returns the maximum Double value.

Namespace:   System.Linq
Assembly:  System.Core (in System.Core.dll)

generic<typename TSource>
static double Max(
	IEnumerable<TSource>^ source,
	Func<TSource, double>^ selector


Type: System.Collections.Generic::IEnumerable<TSource>^

A sequence of values to determine the maximum value of.

Type: System::Func<TSource, Double>^

A transform function to apply to each element.

Return Value

Type: System::Double

The maximum value in the sequence.

Type Parameters


The type of the elements of source.

Exception Condition

source or selector is null.


source contains no elements.

The Max<TSource>(IEnumerable<TSource>^, Func<TSource, Double>^) method uses the Double implementation of IComparable<T> to compare values.

You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Double.

In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

The following code example demonstrates how to use Max<TSource>(IEnumerable<TSource>^, Func<TSource, Int32>^) to determine the maximum value in a sequence of projected values.


This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. To extend the example to this topic, change the body of the selector function.

No code example is currently available or this language may not be supported.

Universal Windows Platform
Available since 4.5
.NET Framework
Available since 3.5
Portable Class Library
Supported in: portable .NET platforms
Available since 2.0
Windows Phone Silverlight
Available since 7.0
Windows Phone
Available since 8.1
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