Queryable.Select<TSource, TResult> Method (IQueryable<TSource>, Expression<Func<TSource, TResult>>)
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Projects each element of a sequence into a new form.
Assembly: System.Core (in System.Core.dll)
public static IQueryable<TResult> Select<TSource, TResult>( this IQueryable<TSource> source, Expression<Func<TSource, TResult>> selector )
Parameters
- source
-
Type:
System.Linq.IQueryable<TSource>
A sequence of values to project.
- selector
-
Type:
System.Linq.Expressions.Expression<Func<TSource, TResult>>
A projection function to apply to each element.
Return Value
Type: System.Linq.IQueryable<TResult>An IQueryable<T> whose elements are the result of invoking a projection function on each element of source.
Type Parameters
- TSource
The type of the elements of source.
- TResult
The type of the value returned by the function represented by selector.
Exception | Condition |
---|---|
ArgumentNullException | source or selector is null. |
This method has at least one parameter of type Expression<TDelegate> whose type argument is one of the Func<T, TResult> types. For these parameters, you can pass in a lambda expression and it will be compiled to an Expression<TDelegate>.
The Select<TSource, TResult>(IQueryable<TSource>, Expression<Func<TSource, TResult>>) method generates a MethodCallExpression that represents calling Select<TSource, TResult>(IQueryable<TSource>, Expression<Func<TSource, TResult>>) itself as a constructed generic method. It then passes the MethodCallExpression to the CreateQuery(Expression) method of the IQueryProvider represented by the Provider property of the source parameter.
The query behavior that occurs as a result of executing an expression tree that represents calling Select<TSource, TResult>(IQueryable<TSource>, Expression<Func<TSource, TResult>>) depends on the implementation of the type of the source parameter. The expected behavior is that it invokes selector on each element of source to project it into a different form.
The following code example demonstrates how to use Select<TSource, TResult>(IQueryable<TSource>, Expression<Func<TSource, TResult>>) to project over a sequence of values.
List<int> range = new List<int> { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 }; // Project the square of each int value. IEnumerable<int> squares = range.AsQueryable().Select(x => x * x); foreach (int num in squares) Console.WriteLine(num); /* This code produces the following output: 1 4 9 16 25 36 49 64 81 100 */
Available since 8
.NET Framework
Available since 3.5
Portable Class Library
Supported in: portable .NET platforms
Silverlight
Available since 2.0
Windows Phone Silverlight
Available since 7.1
Windows Phone
Available since 8.1