Enumerable.Min<'TSource, 'TResult> Method (IEnumerable<'TSource>, Func<'TSource, 'TResult>)
Invokes a transform function on each element of a generic sequence and returns the minimum resulting value.
Assembly: System.Core (in System.Core.dll)
static member Min<'TSource, 'TResult> : source:IEnumerable<'TSource> * selector:Func<'TSource, 'TResult> -> 'TResult
Parameters
- source
-
Type:
System.Collections.Generic.IEnumerable<'TSource>
A sequence of values to determine the minimum value of.
- selector
-
Type:
System.Func<'TSource, 'TResult>
A transform function to apply to each element.
Return Value
Type: TResultThe minimum value in the sequence.
Type Parameters
- TSource
The type of the elements of source.
- TResult
The type of the value returned by selector.
| Exception | Condition |
|---|---|
| ArgumentNullException | source or selector is null. |
If type TResult implements IComparable<'T>, this method uses that implementation to compare values. Otherwise, if type TResult implements IComparable, that implementation is used to compare values.
In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.
The following code example demonstrates how to use Min<'TSource>(IEnumerable<'TSource>, Func<'TSource, Int32>) to determine the minimum value in a sequence of projected values.
Note |
|---|
This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. To extend the example to this topic, change the body of the selector function. |
Available since 8
.NET Framework
Available since 3.5
Portable Class Library
Supported in: portable .NET platforms
Silverlight
Available since 2.0
Windows Phone Silverlight
Available since 7.0
Windows Phone
Available since 8.1
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