Enumerable.Max<TSource> Method (IEnumerable<TSource>, Func<TSource, Int32>)
Invokes a transform function on each element of a sequence and returns the maximum Int32 value.
Assembly: System.Core (in System.Core.dll)
public static int Max<TSource>( this IEnumerable<TSource> source, Func<TSource, int> selector )
Parameters
- source
-
Type:
System.Collections.Generic.IEnumerable<TSource>
A sequence of values to determine the maximum value of.
- selector
-
Type:
System.Func<TSource, Int32>
A transform function to apply to each element.
Type Parameters
- TSource
The type of the elements of source.
| Exception | Condition |
|---|---|
| ArgumentNullException | source or selector is null. |
| InvalidOperationException | source contains no elements. |
The Max<TSource>(IEnumerable<TSource>, Func<TSource, Int32>) method uses the Int32 implementation of IComparable<T> to compare values.
You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Int32.
In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.
The following code example demonstrates how to use Max<TSource>(IEnumerable<TSource>, Func<TSource, Int32>) to determine the maximum value in a sequence of projected values.
class Pet { public string Name { get; set; } public int Age { get; set; } } public static void MaxEx4() { Pet[] pets = { new Pet { Name="Barley", Age=8 }, new Pet { Name="Boots", Age=4 }, new Pet { Name="Whiskers", Age=1 } }; int max = pets.Max(pet => pet.Age + pet.Name.Length); Console.WriteLine( "The maximum pet age plus name length is {0}.", max); } /* This code produces the following output: The maximum pet age plus name length is 14. */
Available since 8
.NET Framework
Available since 3.5
Portable Class Library
Supported in: portable .NET platforms
Silverlight
Available since 2.0
Windows Phone Silverlight
Available since 7.0
Windows Phone
Available since 8.1