Enumerable.Min<TSource> Method (IEnumerable<TSource>, Func<TSource, Double>)
Invokes a transform function on each element of a sequence and returns the minimum Double value.
Namespace: System.Linq
Assembly: System.Core (in System.Core.dll)
public static double Min<TSource>( this IEnumerable<TSource> source, Func<TSource, double> selector )
Type Parameters
- TSource
The type of the elements of source.
Parameters
- source
- Type: System.Collections.Generic.IEnumerable<TSource>
A sequence of values to determine the minimum value of.
- selector
- Type: System.Func<TSource, Double>
A transform function to apply to each element.
Usage Note
In Visual Basic and C#, you can call this method as an instance method on any object of type IEnumerable<TSource>. When you use instance method syntax to call this method, omit the first parameter.| Exception | Condition |
|---|---|
| ArgumentNullException | source or selector is null. |
| InvalidOperationException | source contains no elements. |
The Min<TSource>(IEnumerable<TSource>, Func<TSource, Double>) method uses the Double implementation of IComparable<T> to compare values.
You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Double.
In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.
The following code example demonstrates how to use Min<TSource>(IEnumerable<TSource>, Func<TSource, Int32>) to determine the minimum value in a sequence of projected values.
Note: |
|---|
|
This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. To extend the example to this topic, change the body of the selector function. |
class Pet
{
public string Name { get; set; }
public int Age { get; set; }
}
public static void MinEx4()
{
Pet[] pets = { new Pet { Name="Barley", Age=8 },
new Pet { Name="Boots", Age=4 },
new Pet { Name="Whiskers", Age=1 } };
int min = pets.Min(pet => pet.Age);
outputBlock.Text += String.Format("The youngest animal is age {0}.", min) + "\n";
}
/*
This code produces the following output:
The youngest animal is age 1.
*/
For a list of the operating systems and browsers that are supported by Silverlight, see Supported Operating Systems and Browsers.
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