Enumerable::Sum<TSource> Method (IEnumerable<TSource>^, Func<TSource, Double>^)

.NET Framework (current version)

Computes the sum of the sequence of Double values that are obtained by invoking a transform function on each element of the input sequence.

Namespace: System.Linq
Assembly: System.Core (in System.Core.dll)

Syntax

C++

public:
generic<typename TSource>
[ExtensionAttribute]
static double Sum(
	IEnumerable<TSource>^ source,
	Func<TSource, double>^ selector
)

Parameters

source: Type: System.Collections.Generic::IEnumerable<TSource>^
A sequence of values that are used to calculate a sum.

selector: Type: System::Func<TSource, Double>^
A transform function to apply to each element.

Return Value

Type: System::Double

The sum of the projected values.

Type Parameters

TSource: The type of the elements of source.

Exceptions

Exception	Condition
ArgumentNullException	source or selector is null.

Remarks

This method returns zero if source contains no elements.

You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Double.

In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

Examples

The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>^, Func<TSource, Double>^) to sum the projected values of a sequence.

C++

No code example is currently available or this language may not be supported.

Universal Windows Platform
Available since 8
.NET Framework
Available since 3.5
Portable Class Library
Supported in: portable .NET platforms
Silverlight
Available since 2.0
Windows Phone Silverlight
Available since 7.0
Windows Phone
Available since 8.1