Type.implementsInterface Method
Determines whether a class implements a specified interface type.
var implementsVar = typeInstanceVar.implementsInterface(interfaceType)
Use the implementsInterface method to determine whether a class implements a specific interface. The implementsInterface method verifies both the registered interfaces and registered base class interfaces of the current class.
Description
The following example shows how to use the implementsInterface method to determine whether a class implements a specific interface.
Code
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" > <head id="Head1" runat="server"> <title>Samples</title> </head> <body> <form id="form1" runat="server"> <asp:ScriptManager runat="server" ID="ScriptManager01"> </asp:ScriptManager> <script type="text/javascript"> // Register classes to test. Type.registerNamespace('Samples'); Samples.A = function(){} // Register Samples.A Class Samples.A.registerClass('Samples.A'); Samples.B = function(){} // Register Samples.B Class Samples.B.registerClass('Samples.B'); Samples.C = function(){ // Initialize the base. Samples.C.initializeBase(this); } // Register Samples.C Class as derviving from Samples A and implementing Samples.B Samples.C.registerClass('Samples.C', Samples.A, Samples.B); var isDerived; isDerived = Samples.B.inheritsFrom(Samples.A); // Output: "false". alert(isDerived); isDerived = Samples.C.inheritsFrom(Samples.A); // Output: "true". alert(isDerived); var implementsInterface implementsInterface = Samples.C.implementsInterface(Samples.B); // Output: "true". alert(implementsInterface); </script> </form> </body> </html>
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