Enumerable::Min Method (IEnumerable<Double>^)

 

Returns the minimum value in a sequence of Double values.

Namespace:   System.Linq
Assembly:  System.Core (in System.Core.dll)

public:
[ExtensionAttribute]
static double Min(
	IEnumerable<double>^ source
)

Parameters

source
Type: System.Collections.Generic::IEnumerable<Double>^

A sequence of Double values to determine the minimum value of.

Return Value

Type: System::Double

The minimum value in the sequence.

Exception Condition
ArgumentNullException

source is null.

InvalidOperationException

source contains no elements.

The Min(IEnumerable<Double>^) method uses the Double implementation of IComparable<T> to compare values.

In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

The following code example demonstrates how to use Min(IEnumerable<Double>^) to determine the minimum value in a sequence.

No code example is currently available or this language may not be supported.

Universal Windows Platform
Available since 8
.NET Framework
Available since 3.5
Portable Class Library
Supported in: portable .NET platforms
Silverlight
Available since 2.0
Windows Phone Silverlight
Available since 7.0
Windows Phone
Available since 8.1
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