Min Method (IEnumerable(Double))

Enumerable.Min Method (IEnumerable<Double>)

Returns the minimum value in a sequence of Double values.

Namespace:  System.Linq
Assembly:  System.Core (in System.Core.dll)

public static double Min(
	this IEnumerable<double> source


Type: System.Collections.Generic.IEnumerable<Double>
A sequence of Double values to determine the minimum value of.

Return Value

Type: System.Double
The minimum value in the sequence.

Usage Note

In Visual Basic and C#, you can call this method as an instance method on any object of type IEnumerable<Double>. When you use instance method syntax to call this method, omit the first parameter.


source is null.


source contains no elements.

The Min(IEnumerable<Double>) method uses the Double implementation of IComparable<T> to compare values.

In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

The following code example demonstrates how to use Min(IEnumerable<Double>) to determine the minimum value in a sequence.

      double[] doubles = { 1.5E+104, 9E+103, -2E+103 };

      double min = doubles.Min();

      outputBlock.Text += String.Format("The smallest number is {0}.", min) + "\n";

       This code produces the following output:

       The smallest number is -2E+103.


Supported in: 5, 4, 3

Silverlight for Windows Phone

Supported in: Windows Phone OS 7.1, Windows Phone OS 7.0

XNA Framework

Supported in: Xbox 360, Windows Phone OS 7.0

For a list of the operating systems and browsers that are supported by Silverlight, see Supported Operating Systems and Browsers.

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